The balanced equation for the reaction between aluminum and ethanoic acid is: 2Al(s) + 6CH3COOH(l) → 2Al(CH3COO)3 + 3H2(g)
The balanced equation between ethanoic acid (CH3COOH) and methanol (CH3OH) to form methyl acetate (CH3COOCH3) is: CH3COOH + CH3OH -> CH3COOCH3 + H2O.
The balanced equation for the reaction between aluminum and hydrochloric acid is: 2Al + 6HCl -> 2AlCl3 + 3H2
The balanced equation for the reaction between aluminum hydroxide and permanganic acid is: 2Al(OH)3 + 5H2MnO4 -> 2Al(MnO4)3 + 6H2O + 5MnO2
The balanced equation for the reaction of phosphoric acid (H3PO4) and aluminum (Al) is: 2Al + 3H3PO4 → 3H2 + 2AlPO4
Propanol reacts with ethanoic acid to form propyl ethanoate (ester) and water. The word equation for this reaction is: Propanol + Ethanoic acid -> Propyl ethanoate + Water.
The balanced equation between ethanoic acid (CH3COOH) and methanol (CH3OH) to form methyl acetate (CH3COOCH3) is: CH3COOH + CH3OH -> CH3COOCH3 + H2O.
The balanced equation for the reaction between aluminum and hydrochloric acid is: 2Al + 6HCl -> 2AlCl3 + 3H2
2Al + 3Cl2 -> 2AlCl3
The balanced equation for the reaction between aluminum hydroxide and permanganic acid is: 2Al(OH)3 + 5H2MnO4 -> 2Al(MnO4)3 + 6H2O + 5MnO2
The balanced equation for the reaction of phosphoric acid (H3PO4) and aluminum (Al) is: 2Al + 3H3PO4 → 3H2 + 2AlPO4
Propanol reacts with ethanoic acid to form propyl ethanoate (ester) and water. The word equation for this reaction is: Propanol + Ethanoic acid -> Propyl ethanoate + Water.
The balanced equation for hydrochloric acid reacting with aluminum metal is: 2Al(s) + 6HCl(aq) → 2AlCl3(aq) + 3H2(g).
The balanced equation for ethanoic acid (CH3COOH) behaving as an acid in water is: CH3COOH + H2O ⇌ CH3COO- + H3O+ where CH3COO- is the acetate ion and H3O+ is the hydronium ion. This represents the donation of a proton (H+) from ethanoic acid to water, resulting in the formation of these ions.
The reaction between ethanoic acid and ammonium hydroxide forms ammonium acetate, water, and ammonia gas. The balanced chemical equation for this reaction is: CH3COOH + NH4OH -> NH4CH3COO + H2O + NH3.
The reaction between ethanoic acid (acetic acid) and sodium metal produces sodium acetate, hydrogen gas, and heat. The balanced chemical equation is 2CH3COOH + 2Na -> 2CH3COONa + H2. This is a redox reaction where sodium is oxidized and ethanoic acid is reduced.
The reaction between ethanol and ethanoic acid produces ethyl acetate and water in the presence of a catalyst like concentrated sulfuric acid. The equation for this reaction is: Ethanol + Ethanoic acid → Ethyl acetate + Water
3 H2CO3 + 2 Al(OH)3 --> Al2(CO3)3 + 6 H2O