The balanced equation for the decomposition of lead (II) oxide (PbO) is: 2PbO -> 2Pb + O2
The balanced equation for the decomposition of lead(II) nitrate is: 2Pb(NO3)2(s) → 2PbO(s) + 4NO2(g) + O2(g).
The balanced equation for the decomposition of lead oxide (PbO) is: 2PbO(s) -> 2Pb(s) + O2(g). This indicates that one mole of lead oxide decomposes to form two moles of lead and one mole of oxygen gas.
The balanced equation for the formation of lead oxide is: 2Pb + O2 → 2PbO
The balanced equation for lead chloride is: PbCl2 (s) -> Pb2+ (aq) + 2Cl- (aq)
The balanced equation for the decomposition of lead (II) oxide (PbO) is: 2PbO -> 2Pb + O2
The balanced equation for the decomposition of lead(II) nitrate is: 2Pb(NO3)2(s) → 2PbO(s) + 4NO2(g) + O2(g).
The balanced equation for the decomposition of lead(IV) oxide (PbO2) is 2PbO2 -> 2PbO + O2.
The balanced equation for the decomposition of lead oxide (PbO) is: 2PbO(s) -> 2Pb(s) + O2(g). This indicates that one mole of lead oxide decomposes to form two moles of lead and one mole of oxygen gas.
The balanced equation for the formation of lead oxide is: 2Pb + O2 → 2PbO
The balanced equation for lead chloride is: PbCl2 (s) -> Pb2+ (aq) + 2Cl- (aq)
The chemical equation for the thermal decomposition of lead nitrate is: 2Pb(NO3)2(s) → 2PbO(s) + 4NO2(g) + O2(g)
A balanced equation has equal numbers of each type of atom on each side of the equation..The chemical equation describes the balanced reaction between lead and oxygen to form lead oxide is as follows .4Pb + 3O2 → 2Pb2O3.
Pb2S5
PbS (s) + 2HBr (aq) --> PbBr2 (s) + H2S (g) is the balanced equation for this reaction.
The balanced equation for the reaction between lead (Pb) and hydrochloric acid (HCl) is: Pb + 2HCl -> PbCl2 + H2. This reaction produces lead (II) chloride and hydrogen gas.
PbCl2 is the molecular formula (not chemical equation) of lead(II) chloride.