Sodium hydroxide (NaOH) has a charge of -1.
The correct charge for NaOH (sodium hydroxide) is -1, because sodium (Na) has a charge of +1 and the hydroxide (OH) ion has a charge of -1. When combined in the compound NaOH, the charges balance out to form a neutral molecule.
NaOH - Sodium ion (Na+) has a +1 charge, while hydroxide ion (OH-) has a -1 charge. NaOH - Sodium ion (Na+) has a +1 charge, while hydroxide ion (OH-) has a -1 charge.
The correct charge for the sodium ion (Na^+) is +1, and the correct charge for the hydroxide ion (OH^-) is -1. Together, in the compound NaOH, the charges balance out to form a neutral compound.
The balanced reaction for the reaction between HCl and NaOH is: HCl + NaOH -> NaCl + H2O This equation is already balanced as it shows the conservation of mass and charge.
Yes, NaOH (sodium hydroxide) can conduct electricity when dissolved in water. In solution, it dissociates into ions (Na+ and OH-) which are capable of carrying electric charge. Therefore, NaOH is classified as an ionic conductor.
The correct charge for NaOH (sodium hydroxide) is -1, because sodium (Na) has a charge of +1 and the hydroxide (OH) ion has a charge of -1. When combined in the compound NaOH, the charges balance out to form a neutral molecule.
NaOH - Sodium ion (Na+) has a +1 charge, while hydroxide ion (OH-) has a -1 charge. NaOH - Sodium ion (Na+) has a +1 charge, while hydroxide ion (OH-) has a -1 charge.
Sodium Hydroxide. the OH in NaOH is a polyatomic ion and has a negative charge.
In lye (sodium hydroxide, NaOH), sodium (Na) is the cation with a charge of +1, while hydroxide (OH) is the anion with a charge of -1. Therefore, the correct pair is Na⁺ (sodium ion) and OH⁻ (hydroxide ion), which combine to form the neutral compound NaOH.
The correct charge for the sodium ion (Na^+) is +1, and the correct charge for the hydroxide ion (OH^-) is -1. Together, in the compound NaOH, the charges balance out to form a neutral compound.
NaOH and H2O form a solution of Na+(aq) and OH-(aq) ions (the solvent water, aq, is written as subscripted (aq) ) To make 1 Normal solution you need to know the equivalent of NaOH, which is calculated by dividing Molecular weight by 1, that is 40 divided by 1= 40. So the equivalent weight of NaOH is 40. To make 1 N solution, dissolve 40.00 g of sodium hydroxide in water to make volume of 1 liter.
Sodium hydroxide is an alkali; the pH of the solution is over 7.
Sodium is as the cation Na+; and the anion is (OH)-.
Lye, or sodium hydroxide (NaOH), dissociates in water into sodium ions (Na⁺) and hydroxide ions (OH⁻). The sodium ion carries a +1 charge, while the hydroxide ion carries a -1 charge. Thus, the correct list of ions in lye is Na⁺ and OH⁻.
The balanced reaction for the reaction between HCl and NaOH is: HCl + NaOH -> NaCl + H2O This equation is already balanced as it shows the conservation of mass and charge.
Yes, NaOH (sodium hydroxide) can conduct electricity when dissolved in water. In solution, it dissociates into ions (Na+ and OH-) which are capable of carrying electric charge. Therefore, NaOH is classified as an ionic conductor.
The chemical equation for the reaction between eugenol and NaOH is: C10H12O2 (eugenol) + NaOH → C10H11O2Na + H2O. In this reaction, eugenol undergoes a base-catalyzed condensation reaction with NaOH to form sodium eugenolate and water.