NaOH strips the proton from eugenol giving the oxygen on eugenol a negative charge, a sodium cation, and water
The reaction of eugenol (C10H12O2) with sodium hydroxide (NaOH) can be represented as follows: C10H12O2 + NaOH → Sodium eugenolate + Water. The product is soluble in water because the sodium eugenolate formed is a salt, which dissociates into ions (eugenolate anion and sodium cation) in water, allowing it to dissolve in the polar solvent.
The balanced equation for the reaction between acetic acid (HC2H3O2) and sodium hydroxide (NaOH) is: HC2H3O2 + NaOH → NaC2H3O2 + H2O
The chemical equation for the reaction of TiOCl with NaOH is: TiOCl2 + 2 NaOH → Ti(OH)2 + 2 NaCl
The balanced equation for Na2O + H2O → 2 NaOH is: Na2O + H2O → 2 NaOH
When NaOH dissolves in water, it dissociates into Na+ and OH- ions. The equation representing this ionization reaction is: NaOH (s) → Na+ (aq) + OH- (aq). If you want a chemical equation showing the complete dissociation of NaOH in water, it would be: NaOH (s) → Na+ (aq) + OH- (aq).
The reaction of eugenol (C10H12O2) with sodium hydroxide (NaOH) can be represented as follows: C10H12O2 + NaOH → Sodium eugenolate + Water. The product is soluble in water because the sodium eugenolate formed is a salt, which dissociates into ions (eugenolate anion and sodium cation) in water, allowing it to dissolve in the polar solvent.
The chemical equation is:C6H8O7 + 3 NaOH = C6H5O7Na3 + 3 H2O
The balanced equation for the reaction between acetic acid (HC2H3O2) and sodium hydroxide (NaOH) is: HC2H3O2 + NaOH → NaC2H3O2 + H2O
The chemical equation for the reaction of TiOCl with NaOH is: TiOCl2 + 2 NaOH → Ti(OH)2 + 2 NaCl
The balanced equation for Na2O + H2O → 2 NaOH is: Na2O + H2O → 2 NaOH
When NaOH dissolves in water, it dissociates into Na+ and OH- ions. The equation representing this ionization reaction is: NaOH (s) → Na+ (aq) + OH- (aq). If you want a chemical equation showing the complete dissociation of NaOH in water, it would be: NaOH (s) → Na+ (aq) + OH- (aq).
The net ionic equation for HF and NaOH is: HF (aq) + NaOH (aq) -> H2O (l) + NaF (aq).
The reaction equation between NaOH and potassium hydrogen tartrate (KHT) is: 2KHT + 2NaOH → 2KNaTartrate + 2H2O
The balanced equation for the reaction between amidosulfuric acid (NH2SO3H) and sodium hydroxide (NaOH) is: NH2SO3H + NaOH → NaHSO3 + H2O
H3PO4 + NaOH ----> Na2HPO4 + H2O
1 HCl + 1 NaOH ---> 1 NaCl + 1 H(OH)
NaOH and HCl are the reactants; water and ammonium chloride are the products.