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but actually its negative
Rb+
The rubidium ion, Rb+, has a charge of +1. This means it has lost one electron, leaving it with one more proton than electrons, resulting in a net positive charge.
An atom of rubidium-85 becomes a rubidium ion with a 1 charge by losing one electron. Since rubidium-85 has 37 protons and 37 electrons, losing one electron would result in the ion having 37 protons and 36 electrons, giving it a net charge of +1.
The formula for rubidium nitride is Rb3N, as rubidium has a +1 charge and nitrogen has a -3 charge, requiring three rubidium ions to balance one nitrogen ion.
A rubidium atom is larger than a neutral atom because, when it loses an electron to become an ion, it loses an electron from the outermost shell, increasing the effective nuclear charge which attracts the remaining electrons closer to the nucleus, reducing the size of the ion compared to the atom.
Rb+
The rubidium ion, Rb+, has a charge of +1. This means it has lost one electron, leaving it with one more proton than electrons, resulting in a net positive charge.
An atom of rubidium-85 becomes a rubidium ion with a 1 charge by losing one electron. Since rubidium-85 has 37 protons and 37 electrons, losing one electron would result in the ion having 37 protons and 36 electrons, giving it a net charge of +1.
When Rubidium (Rb) has an atomic number of 37, it has one electron in its outermost shell. By losing this single electron, Rubidium forms a cation with a charge of +1. Therefore, the charge of the Rubidium ion would be +1, commonly represented as Rb⁺.
The formula for rubidium nitride is Rb3N, as rubidium has a +1 charge and nitrogen has a -3 charge, requiring three rubidium ions to balance one nitrogen ion.
An atom of rubidium-85 becomes a rubidium ion with a plus 1 charge by losing one of its outermost electrons. This process typically occurs during a chemical reaction or ionization, where the atom interacts with other atoms or energy sources. Upon losing the electron, the atom, now having one less negative charge, becomes positively charged, resulting in the rubidium ion (Rb⁺).
Rubidium has an atomic number of 37, which means it has 37 protons and, when neutral, 37 electrons. When rubidium loses one electron, it will have 36 electrons remaining. Since it has one more proton than electrons, the resulting ion will have a charge of +1, making it a rubidium ion (Rb⁺).
Two: the rubidium ion Rb+ and the nitrate ion NO3-
Elements in group one of the periodic table; Lithium, Sodium, potassium, rubidium, caesium and rubidium, will form ions with a positive charge of one.
A rubidium atom is larger than a neutral atom because, when it loses an electron to become an ion, it loses an electron from the outermost shell, increasing the effective nuclear charge which attracts the remaining electrons closer to the nucleus, reducing the size of the ion compared to the atom.
Rubidium is a group 1 metal with just one valence electron. It therefore forms the ion Rb+ as it loses the electron. The ionic formula is Rb+ Cl-
If rubidium (Rb) loses 1 electron, it will have a charge of +1 because it is losing a negative electron, resulting in a positive charge.