answersLogoWhite

0

The diatomic molecule of oxygen is O2 (the question is confuse).

User Avatar

Wiki User

10y ago

What else can I help you with?

Related Questions

How many number of moles of atom are present in 540 grams of glucose?

To find the number of moles of glucose (C₆H₁₂O₆) in 540 grams, first calculate the molar mass of glucose: (6 × 12.01) + (12 × 1.008) + (6 × 16.00) = 180.18 g/mol. Then, use the formula: moles = mass (g) / molar mass (g/mol). Thus, the number of moles in 540 grams of glucose is 540 g / 180.18 g/mol ≈ 3.00 moles.


What is the chemical formula of Mg and o?

The chemical formula of magnesium is Mg and the chemical formula of oxygen is O.


What is the formula mass of nitrogen monoxide in atomic mass?

The formula mass of a compound is the sum of the atomic masses of all the atoms in the chemical formula. For nitrogen monoxide, the chemical formula is NO. The atomic mass of nitrogen (N) is approximately 14.01 g/mol, and for oxygen (O) is approximately 16 g/mol. Therefore, the formula mass of nitrogen monoxide (NO) is approximately 14.01 + 16 = 30.01 g/mol.


What is the chemical formula for Mg and O?

The chemical formula for magnesium is Mg, and for oxygen, it is O₂.


Determine the empirical formula what compound if a sample contains 0.104 mol K 0.052 mol C and 0.156 mol O?

To find the empirical formula, we need to determine the ratio of each element in the compound. First, find the moles of each element: K = 0.104 mol C = 0.052 mol O = 0.156 mol Next, divide each mole value by the smallest mole value to get the ratio: K = 0.104 mol / 0.052 mol = 2 C = 0.052 mol / 0.052 mol = 1 O = 0.156 mol / 0.052 mol = 3 Therefore, the empirical formula is K2CO3.


What is the molecular formula of a compound if its empirical formula is CFBrO and its molar mass is 381.01 gmol?

To determine the molecular formula from the empirical formula CFBrO, we first calculate the molar mass of the empirical formula: C (12.01 g/mol) + F (19.00 g/mol) + Br (79.90 g/mol) + O (16.00 g/mol) = 126.91 g/mol. Next, we divide the given molar mass (381.01 g/mol) by the empirical formula mass (126.91 g/mol) to find the ratio: 381.01 g/mol ÷ 126.91 g/mol ≈ 3. The molecular formula is thus (CFBrO)₃, or C₃F₃Br₃O₃.


What is a molecular formula 264g with a empirical formula of C3H4O3?

To determine the molecular formula from the empirical formula (C₃H₄O₃) and the given molar mass (264 g), first, calculate the molar mass of the empirical formula: C (12.01 g/mol) × 3 + H (1.01 g/mol) × 4 + O (16.00 g/mol) × 3 = 88.11 g/mol. Next, divide the given molar mass by the empirical formula mass: 264 g / 88.11 g/mol ≈ 3. This means the molecular formula is three times the empirical formula, resulting in C₉H₁₂O₉.


What is the empirical formula of a substance that consists of 30704g aluminum and 3.295g oxygen?

The molar mass of aluminum is 26.98 g/mol and the molar mass of oxygen is 16.00 g/mol. To find the empirical formula, we first need to convert the given masses to moles. 30704g Al = 30704g / 26.98 g/mol = 1137.41 mol Al 3.295g O = 3.295g / 16.00 g/mol = 0.206 mol O Next, we determine the ratio between the two elements. Al : O = 1137.41 mol : 0.206 mol ≈ 5528 : 1 The empirical formula for the substance is Al5528O.


What is the formula mass for NaClO?

The formula mass for NaClO (sodium hypochlorite) is calculated by adding the atomic masses of each element in the compound: Na (sodium) = 22.99 g/mol Cl (chlorine) = 35.45 g/mol O (oxygen) = 16.00 g/mol Formula mass = 22.99 + 35.45 + 16.00 = 74.44 g/mol


What is the formula mass of h20?

The formula mass of H2O (water) is calculated by adding the atomic masses of the elements present in the compound. The atomic masses of hydrogen (H) and oxygen (O) are approximately 1 and 16, respectively. Therefore, the formula mass of H2O is 1 (atomic mass of H) * 2 (number of hydrogen atoms) + 16 (atomic mass of O) = 18.


What is the chemical formula of arabinose?

The chemical formula of arabinose is C₅H₁₀O₅.


What is the chemical formula of carbon dioxide o?

The chemical formula of carbon dioxide is CO2.