The diatomic molecule of oxygen is O2 (the question is confuse).
The chemical formula of magnesium is Mg and the chemical formula of oxygen is O.
The chemical formula for magnesium is Mg, and for oxygen, it is O₂.
The molar mass of aluminum is 26.98 g/mol and the molar mass of oxygen is 16.00 g/mol. To find the empirical formula, we first need to convert the given masses to moles. 30704g Al = 30704g / 26.98 g/mol = 1137.41 mol Al 3.295g O = 3.295g / 16.00 g/mol = 0.206 mol O Next, we determine the ratio between the two elements. Al : O = 1137.41 mol : 0.206 mol ≈ 5528 : 1 The empirical formula for the substance is Al5528O.
The chemical formula of carbon dioxide is CO2.
The chemical formula for citric acid is C6H8O7.
To find the number of moles of glucose (C₆H₁₂O₆) in 540 grams, first calculate the molar mass of glucose: (6 × 12.01) + (12 × 1.008) + (6 × 16.00) = 180.18 g/mol. Then, use the formula: moles = mass (g) / molar mass (g/mol). Thus, the number of moles in 540 grams of glucose is 540 g / 180.18 g/mol ≈ 3.00 moles.
The chemical formula of magnesium is Mg and the chemical formula of oxygen is O.
The formula mass of a compound is the sum of the atomic masses of all the atoms in the chemical formula. For nitrogen monoxide, the chemical formula is NO. The atomic mass of nitrogen (N) is approximately 14.01 g/mol, and for oxygen (O) is approximately 16 g/mol. Therefore, the formula mass of nitrogen monoxide (NO) is approximately 14.01 + 16 = 30.01 g/mol.
The chemical formula for magnesium is Mg, and for oxygen, it is O₂.
To find the empirical formula, we need to determine the ratio of each element in the compound. First, find the moles of each element: K = 0.104 mol C = 0.052 mol O = 0.156 mol Next, divide each mole value by the smallest mole value to get the ratio: K = 0.104 mol / 0.052 mol = 2 C = 0.052 mol / 0.052 mol = 1 O = 0.156 mol / 0.052 mol = 3 Therefore, the empirical formula is K2CO3.
To determine the molecular formula from the empirical formula CFBrO, we first calculate the molar mass of the empirical formula: C (12.01 g/mol) + F (19.00 g/mol) + Br (79.90 g/mol) + O (16.00 g/mol) = 126.91 g/mol. Next, we divide the given molar mass (381.01 g/mol) by the empirical formula mass (126.91 g/mol) to find the ratio: 381.01 g/mol ÷ 126.91 g/mol ≈ 3. The molecular formula is thus (CFBrO)₃, or C₃F₃Br₃O₃.
To determine the molecular formula from the empirical formula (C₃H₄O₃) and the given molar mass (264 g), first, calculate the molar mass of the empirical formula: C (12.01 g/mol) × 3 + H (1.01 g/mol) × 4 + O (16.00 g/mol) × 3 = 88.11 g/mol. Next, divide the given molar mass by the empirical formula mass: 264 g / 88.11 g/mol ≈ 3. This means the molecular formula is three times the empirical formula, resulting in C₉H₁₂O₉.
The molar mass of aluminum is 26.98 g/mol and the molar mass of oxygen is 16.00 g/mol. To find the empirical formula, we first need to convert the given masses to moles. 30704g Al = 30704g / 26.98 g/mol = 1137.41 mol Al 3.295g O = 3.295g / 16.00 g/mol = 0.206 mol O Next, we determine the ratio between the two elements. Al : O = 1137.41 mol : 0.206 mol ≈ 5528 : 1 The empirical formula for the substance is Al5528O.
The formula mass for NaClO (sodium hypochlorite) is calculated by adding the atomic masses of each element in the compound: Na (sodium) = 22.99 g/mol Cl (chlorine) = 35.45 g/mol O (oxygen) = 16.00 g/mol Formula mass = 22.99 + 35.45 + 16.00 = 74.44 g/mol
The formula mass of H2O (water) is calculated by adding the atomic masses of the elements present in the compound. The atomic masses of hydrogen (H) and oxygen (O) are approximately 1 and 16, respectively. Therefore, the formula mass of H2O is 1 (atomic mass of H) * 2 (number of hydrogen atoms) + 16 (atomic mass of O) = 18.
The chemical formula of arabinose is C₅H₁₀O₅.
The chemical formula of carbon dioxide is CO2.