Since chlorate is a univalent anion, if such a compound exists it would have the formula Ni(ClO3)4.
The chemical name for Sn(ClO3)4 is tin(IV) chlorate.
When lead (IV) sulfate reacts with tin (II) chlorate, the lead (IV) cation (Pb^4+) will combine with the chlorate anion (ClO3^-) to form lead (IV) chlorate, Pb(ClO3)4. The tin (II) cation (Sn^2+) will combine with the sulfate anion (SO4^2-) to form tin (II) sulfate, SnSO4.
There are countless chemical formulas, as they are used to represent all elements and compounds. The number of possible chemical formulas is theoretically infinite, as new compounds can be created through different combinations of elements.
NiCl4 is the chemical formula for nickel(IV) chloride, which is an unstable compound. It is a coordination complex that contains a nickel ion in the +4 oxidation state surrounded by four chloride ions. Nickel(IV) compounds are quite rare due to their high oxidation state.
nickel is in period 4. Specifically period 4 group 10
The chemical name for Sn(ClO3)4 is tin(IV) chlorate.
Nickel is a chemical element, metal placed in the periodic table of Mendeleev in the group 10 and period 4.
The correct formula for Molybdenum IV Chlorate is Mo(ClO3)4.
crystal galena hernatite lazurite
Formula: W(ClO3)4
Formulas are: Sn(NO3)2 and Sn(NO3)4.
When lead (IV) sulfate reacts with tin (II) chlorate, the lead (IV) cation (Pb^4+) will combine with the chlorate anion (ClO3^-) to form lead (IV) chlorate, Pb(ClO3)4. The tin (II) cation (Sn^2+) will combine with the sulfate anion (SO4^2-) to form tin (II) sulfate, SnSO4.
There are countless chemical formulas, as they are used to represent all elements and compounds. The number of possible chemical formulas is theoretically infinite, as new compounds can be created through different combinations of elements.
NiCl4 is the chemical formula for nickel(IV) chloride, which is an unstable compound. It is a coordination complex that contains a nickel ion in the +4 oxidation state surrounded by four chloride ions. Nickel(IV) compounds are quite rare due to their high oxidation state.
To find the moles of cesium chlorate needed to produce 2.7 moles of oxygen gas, use the balanced chemical equation for the decomposition of cesium chlorate: 2CsClO3 -> 2CsCl + 3O2 From the equation, it shows that 2 moles of cesium chlorate produce 3 moles of oxygen gas. Therefore, you will need (2/3) * 2.7 = 1.8 moles of cesium chlorate to produce 2.7 moles of oxygen gas.
Nickel has 3 (three) electron shells.
NaClO4 has 1+1+4=6 atoms while CuCl has only two (1+1=2)