Tin IV Chlorate
Sn(CLO3)2 Tin (II) has a positive 2 charge and Chlorate has a (-1) charge so you need to cholrates to one Tin.
Tin and Lead are both metals with oxidation numbers of 2+ and 4+, so the two equations for Lead (Pb) are 2Pb + O2 ---> 2PbO and Pb + O2 ---> PbO2 The equations for Tin (Sn) look the same ... just substitute Sn where you see Pb.
Since chlorate is a univalent anion, if such a compound exists it would have the formula Ni(ClO3)4.
The chemical formula of tin IV acetate is Sn(C2H3O2)4.
The formula for the tin four ion is Sn+4
Formula: Sn(HCO3)4
Sn(CLO3)2 Tin (II) has a positive 2 charge and Chlorate has a (-1) charge so you need to cholrates to one Tin.
Tin and Lead are both metals with oxidation numbers of 2+ and 4+, so the two equations for Lead (Pb) are 2Pb + O2 ---> 2PbO and Pb + O2 ---> PbO2 The equations for Tin (Sn) look the same ... just substitute Sn where you see Pb.
Formulas are: Sn(NO3)2 and Sn(NO3)4.
Since chlorate is a univalent anion, if such a compound exists it would have the formula Ni(ClO3)4.
Tin(IV) acetate has the chemical formula (not symbol) Sn(C2H3O2)4.
Sn(OH)4
Sn(OH)2
Sn(OH)4
Formula: Sn(IO)4
The chemical formula of tin IV acetate is Sn(C2H3O2)4.
Assuming you're asking about the chemical formula... Sn(CH3COO)4