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The coefficient for Cl2 should be 1 in order for the reaction to be balanced. This means there should be 1 molecule of Cl2 reacting with 1 atom of Mg to form 1 molecule of MgCl2.
To balance the reaction Cl2 + KI -> KCl + I2, you just need to place a coefficient of 2 in front of KCl to balance the number of chlorine atoms on both sides of the reaction. The balanced reaction is Cl2 + 2KI -> 2KCl + I2.
To balance the reaction Cl2 + 2Kl -> 2KCl + L2, you need to adjust the coefficients for each compound so that the number of each type of atom is the same on both sides of the reaction arrow. By changing the coefficient of KI to 2, the number of K and I atoms are balanced, and the reaction is balanced as a result.
To find the number of moles of Cl2 in 7.1g of chlorine, you need to divide the mass of Cl2 by its molar mass. The molar mass of Cl2 is 70.9 g/mol. Therefore, 7.1g / 70.9 g/mol = 0.1 moles of Cl2.
Cl2
1
The coefficient for Cl2 should be 1 in order for the reaction to be balanced. This means there should be 1 molecule of Cl2 reacting with 1 atom of Mg to form 1 molecule of MgCl2.
In + Cl2 = InCl3 this is the equation for indium trichloride next, you have to balance it, so: 2 In + 3 Cl2 = 2 InCl3 therefore the coefficient would of indium trichloride would be 2
To balance the reaction Cl2 + KI -> KCl + I2, you just need to place a coefficient of 2 in front of KCl to balance the number of chlorine atoms on both sides of the reaction. The balanced reaction is Cl2 + 2KI -> 2KCl + I2.
To balance the chemical equation CH4 + Cl2 → CCl4 + HCl, you need to ensure that the number of each type of atom is the same on both sides of the equation. Start by counting the number of each type of atom on each side: 1 carbon, 4 hydrogen, and 2 chlorine on the left, and 1 carbon, 1 hydrogen, and 1 chlorine on the right. To balance the equation, you can adjust the coefficients in front of each compound. The balanced equation is CH4 + 4Cl2 → CCl4 + 4HCl.
Cl2 is non polar.So there are london bonds.
Ca + Cl2 ----> CaCl Step 1) Ca + Cl2 ----> 2 CaCl There are 2 Cl's on the reaction side so you need 2 on the Product side Step 2) 2Ca + Cl2 ----> 2 CaCl There are now 2 Ca on the product side and you need 2 on the reactant side Voila!
To balance the reaction Cl2 + 2Kl -> 2KCl + L2, you need to adjust the coefficients for each compound so that the number of each type of atom is the same on both sides of the reaction arrow. By changing the coefficient of KI to 2, the number of K and I atoms are balanced, and the reaction is balanced as a result.
You start with methane (CH4 ) and chlorine ( Cl2) and react them thus:- CH4 + Cl2 → CH3Cl + HCl CH3Cl + Cl2 → CH2Cl2 + HCl CH2Cl2 + Cl2 → CHCl3 + HCl
If the concentration of Cl2 is decreased, the reaction will shift to the left to try to replace the lost Cl2. This means more C2H4 will react with any remaining Cl2 to form more C2H4Cl2 until a new equilibrium is reached with a lower concentration of Cl2.
2K + Cl2 --> 2KCl
The balanced equation for the reaction between sodium (Na) and chlorine (Cl2) to form sodium chloride (NaCl) is 2Na + Cl2 -> 2NaCl. This equation is balanced because it has an equal number of each type of atom on both sides of the reaction arrow.