Fe3+ combines with PO43- ion to form FePO4
FePO4 is called ferric phosphate or iron(III) phosphate
The answer is ; Hg3(PO4)2, Fe(NO3)3
PO43- is the phosphate ion.
I believe that what you have in mind is the phosphate radical, PO4. While this radical appears in many compounds, it is not itself a compound.
Calcium ions (Ca^2+) and phosphate ions (PO4^3-) can combine to form the compound calcium phosphate (Ca3(PO4)2) through ionic bonding. In this compound, three calcium ions balance out the charge of two phosphate ions to achieve overall electroneutrality.
Yes, you need to put the PO4 in parentheses and add a 3 subscript to indicate that there are 3 phosphate ions in the compound. The product of Na3PO4 + NiCl2 would be Ni3(PO4)2 + 6NaCl.
That compound is called rubidium phosphate.
T he correct formula for iron(III) phosphate is Fe3(PO4)2.
The compound Be3(PO4)2 is beryllium phosphate. It consists of beryllium ions (Be2+) and phosphate ions (PO4^3-).
FePO4, or iron(III) phosphate, has a neutral overall charge. In this compound, iron (Fe) typically has a +3 oxidation state, while the phosphate ion (PO4) has a -3 charge. Thus, the charges balance out, resulting in a neutral compound.
The answer is ; Hg3(PO4)2, Fe(NO3)3
PO43- is the phosphate ion.
I believe that what you have in mind is the phosphate radical, PO4. While this radical appears in many compounds, it is not itself a compound.
For example a calcium phosphate as Ca3(PO4)2.
do's PO4 com[ound do's PO4 com[ound
Calcium ions (Ca^2+) and phosphate ions (PO4^3-) can combine to form the compound calcium phosphate (Ca3(PO4)2) through ionic bonding. In this compound, three calcium ions balance out the charge of two phosphate ions to achieve overall electroneutrality.
The ionic compound for Ca3(PO4)2 is calcium phosphate. It consists of calcium ions (Ca2+) and phosphate ions (PO43-) in a 3:2 ratio.
Yes, you need to put the PO4 in parentheses and add a 3 subscript to indicate that there are 3 phosphate ions in the compound. The product of Na3PO4 + NiCl2 would be Ni3(PO4)2 + 6NaCl.