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The molar mass of FeCl3 is 162.20 g/mol. First, convert 40.0 g to moles by dividing by the molar mass. Then, calculate the concentration in mol/L by dividing the moles of FeCl3 by the volume of the solution in liters (0.275 L).
To prepare a 0.1N solution of NaOH, dissolve 4g of NaOH pellets in enough distilled water to make 1 liter of solution. This will result in a solution with a concentration of 0.1N of NaOH.
what is the molarity of a solution prepared by dissolving 36.0g of NaOH in enough water to make 1.50 liter of solution?
To find the molarity, first calculate the number of moles of sodium sulphate using its molar mass. Sodium sulphate's molar mass is 142.04 g/mol. Next, divide the number of moles by the volume in liters (125 ml = 0.125 L) to get the molarity. This will give you the molarity of the sodium sulphate solution.
The question is a little ambiguous so I'll answer it the best way I can. Concentration (M) is the number of moles of a substance divided by the volume that it is dissolved in. This leads to the expression c = n/V Where n is the number of moles, V is the volume in litres and c is the concentration. In answer to the question, 500 ml of 0.25M solution can be prepared as follows: c = n/V Therefor: 0.25 = n/0.5L n = 0.125 mol 500ml of an 0.25M solution can be prepared by dissolving 0.125 mol of the substance in 500ml (providing it dissolves).
The molar mass of FeCl3 is 162.20 g/mol. First, convert 40.0 g to moles by dividing by the molar mass. Then, calculate the concentration in mol/L by dividing the moles of FeCl3 by the volume of the solution in liters (0.275 L).
20.2 g of CuCl2 = .1502 mol CuCl2 M=mol/L M=.1502 mol/L
The concentration of the resulting solution is calculated by adding the mass of the solute to the final volume of the solution. In this case, the 12.00 mL sample contains 13.3g of ammonium sulfate. When diluted to a total volume of 12.00 mL + 57.00 mL = 69.00 mL, the concentration of the resulting solution can be determined.
To prepare a 0.1N solution of NaOH, dissolve 4g of NaOH pellets in enough distilled water to make 1 liter of solution. This will result in a solution with a concentration of 0.1N of NaOH.
hypertonic solution
to make the solution basic enough so that NH be prepared for Fmoc protection
what is the molarity of a solution prepared by dissolving 36.0g of NaOH in enough water to make 1.50 liter of solution?
To find the molarity, first calculate the number of moles of sodium sulphate using its molar mass. Sodium sulphate's molar mass is 142.04 g/mol. Next, divide the number of moles by the volume in liters (125 ml = 0.125 L) to get the molarity. This will give you the molarity of the sodium sulphate solution.
To prepare a 50mm glucose solution, you would need to dissolve 9g of glucose in enough water to make 100mL of solution. This would give you a solution with a concentration of 50mm (millimolar).
The question is a little ambiguous so I'll answer it the best way I can. Concentration (M) is the number of moles of a substance divided by the volume that it is dissolved in. This leads to the expression c = n/V Where n is the number of moles, V is the volume in litres and c is the concentration. In answer to the question, 500 ml of 0.25M solution can be prepared as follows: c = n/V Therefor: 0.25 = n/0.5L n = 0.125 mol 500ml of an 0.25M solution can be prepared by dissolving 0.125 mol of the substance in 500ml (providing it dissolves).
White Cornstarch is clear, but it may make your solution a bit hazy if it high enough concentration. the color of cornstart sulotion is white
C1V1 = C2V24 x .04 = 1 x V2V2 = (4 x .04)/1= 160mLTherefore the volume of water that needs to be added is 120mL (minus the original volume).