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What is the concentration of FeCl3 in a solution prepared by dissolving 40.0 g of FeCl3 in enough water to make 275 mL of solution?

The molar mass of FeCl3 is 162.20 g/mol. First, convert 40.0 g to moles by dividing by the molar mass. Then, calculate the concentration in mol/L by dividing the moles of FeCl3 by the volume of the solution in liters (0.275 L).


How an exact of 0.1N solution of NaOH can be prepared?

To prepare a 0.1N solution of NaOH, dissolve 4g of NaOH pellets in enough distilled water to make 1 liter of solution. This will result in a solution with a concentration of 0.1N of NaOH.


What is the molarity of a solution made by dissolving 3.09 moles of Nacl in 1.50 L of solution?

what is the molarity of a solution prepared by dissolving 36.0g of NaOH in enough water to make 1.50 liter of solution?


What is the molarity of a solution made by dissolving 23.4g of sodium sulphate in enough water to make up a 125ml solution?

To find the molarity, first calculate the number of moles of sodium sulphate using its molar mass. Sodium sulphate's molar mass is 142.04 g/mol. Next, divide the number of moles by the volume in liters (125 ml = 0.125 L) to get the molarity. This will give you the molarity of the sodium sulphate solution.


How is 500 ml of 0.25-M solution prepared?

The question is a little ambiguous so I'll answer it the best way I can. Concentration (M) is the number of moles of a substance divided by the volume that it is dissolved in. This leads to the expression c = n/V Where n is the number of moles, V is the volume in litres and c is the concentration. In answer to the question, 500 ml of 0.25M solution can be prepared as follows: c = n/V Therefor: 0.25 = n/0.5L n = 0.125 mol 500ml of an 0.25M solution can be prepared by dissolving 0.125 mol of the substance in 500ml (providing it dissolves).

Related Questions

What is the concentration of FeCl3 in a solution prepared by dissolving 40.0 g of FeCl3 in enough water to make 275 mL of solution?

The molar mass of FeCl3 is 162.20 g/mol. First, convert 40.0 g to moles by dividing by the molar mass. Then, calculate the concentration in mol/L by dividing the moles of FeCl3 by the volume of the solution in liters (0.275 L).


What is the molarity of a solution prepared by dissolving 20.00g CaCl2 in enough water to make 1.00L of solution?

20.2 g of CuCl2 = .1502 mol CuCl2 M=mol/L M=.1502 mol/L


Solution is prepared by dissolving 13.3g ammonium sulfate in enough water to make 100.0 mL of stock solution A 12.00 mL sample of this stock solution is added 57.00 mL of water Calculate the concen?

The concentration of the resulting solution is calculated by adding the mass of the solute to the final volume of the solution. In this case, the 12.00 mL sample contains 13.3g of ammonium sulfate. When diluted to a total volume of 12.00 mL + 57.00 mL = 69.00 mL, the concentration of the resulting solution can be determined.


How an exact of 0.1N solution of NaOH can be prepared?

To prepare a 0.1N solution of NaOH, dissolve 4g of NaOH pellets in enough distilled water to make 1 liter of solution. This will result in a solution with a concentration of 0.1N of NaOH.


Can be prepared by adding enough amount of soute in a lesser amount of solvent?

hypertonic solution


Why do you add sodium carbonate solution for Fmoc ptotection?

to make the solution basic enough so that NH be prepared for Fmoc protection


What is the molarity of a solution made by dissolving 3.09 moles of Nacl in 1.50 L of solution?

what is the molarity of a solution prepared by dissolving 36.0g of NaOH in enough water to make 1.50 liter of solution?


What is the molarity of a solution made by dissolving 23.4g of sodium sulphate in enough water to make up a 125ml solution?

To find the molarity, first calculate the number of moles of sodium sulphate using its molar mass. Sodium sulphate's molar mass is 142.04 g/mol. Next, divide the number of moles by the volume in liters (125 ml = 0.125 L) to get the molarity. This will give you the molarity of the sodium sulphate solution.


How can you prepare 50mm glucose?

To prepare a 50mm glucose solution, you would need to dissolve 9g of glucose in enough water to make 100mL of solution. This would give you a solution with a concentration of 50mm (millimolar).


How is 500 ml of 0.25-M solution prepared?

The question is a little ambiguous so I'll answer it the best way I can. Concentration (M) is the number of moles of a substance divided by the volume that it is dissolved in. This leads to the expression c = n/V Where n is the number of moles, V is the volume in litres and c is the concentration. In answer to the question, 500 ml of 0.25M solution can be prepared as follows: c = n/V Therefor: 0.25 = n/0.5L n = 0.125 mol 500ml of an 0.25M solution can be prepared by dissolving 0.125 mol of the substance in 500ml (providing it dissolves).


What color is a cornstarch solution?

White Cornstarch is clear, but it may make your solution a bit hazy if it high enough concentration. the color of cornstart sulotion is white


What is the molar concentration of a solution made by dissolving 4.0g of NaOH in enough water to make 1.0 L of solution?

C1V1 = C2V24 x .04 = 1 x V2V2 = (4 x .04)/1= 160mLTherefore the volume of water that needs to be added is 120mL (minus the original volume).