Use the equation M(initial)*V(initial)=M(final)*V(final).
In this case, M(initial) is 0.200 M NaCl. V(initial) is 20.0mL. V(final) is 250.0mL. You are solving for M(final).
To solve, you rearrange the equation so M(final)=(M(initial)*V(initial))/V(final), which gives you (0.200*20.0)/250. The answer is 0.016 M for M(final).
You don't need to convert mL to L in this type of problem. You can if you want, but you will end up with the same answer. It's just an extra unnecessary step, unless the question is asking for a Volume in L. But in this case you were asked for concentration (Molarity), so no volume conversions were necessary.
concentration = molarity molarity= moles/ volume (in liters) H=1g F= 19g 1gH+ 19gF= 20gHF 20gHF x (1 mol HF/ 20gHF) = 1mol HF 2.0x10^2ml= 200ml x (1L/1000mL)= .200L Concentration= 1 mol HF/ .200L Concentration= 5M
40mn
Density of etyl acetate
you can only use the following glassware 5 10 20 25 and 50ml pipette 50 100 200 or 500ml volumetric flasks
1 mole of NaCl is 58.44 g 200 g NaCl * (1 mol NaCl/58.44 g NaCl) = 3.422 mol NaCl There are about 3.4 moles in 200 grams of NaCl.
The concentration is 1 mol/L or 5,611 g KOH/100 mL solution.
200ml of solution x 20% of alcohol = 40ml of alcohol..
concentration = molarity molarity= moles/ volume (in liters) H=1g F= 19g 1gH+ 19gF= 20gHF 20gHF x (1 mol HF/ 20gHF) = 1mol HF 2.0x10^2ml= 200ml x (1L/1000mL)= .200L Concentration= 1 mol HF/ .200L Concentration= 5M
40mn
a lot
Density of etyl acetate
It is 2.5 molar. The reason for this is that molarity means moles per litre. You have to multiply by 5 to get from 200ml to a litre, so you have to do the same with the moles.
you can only use the following glassware 5 10 20 25 and 50ml pipette 50 100 200 or 500ml volumetric flasks
200mL equates to 2dL (deciliters).
Change 200mL into decimal.
yes 200ml is less that an 124 inch
Answer:170mL of 5% acid solution and 30mL of 25% solution must be mixed to produce 200mL of a 8% acid solutionLet x = 5% acid solutiony = 25% acid solution Equations:x + y = 200mL ----equation (1)0.05x + 0.25y = 0.08 * 2000.05x + 0.25y = 16multiplying by 1005x + 25y = 1600 ----equation (2)eliminating equations (1) and (2)-5(x + y = 200)-5-5x -5y = -10005x +25y = 1600=========20y = 600y=30substitute x=30 to equation (1)x + 30 = 200x = 200 - 30x = 170thus 170mL of 5% solution and 30mL of 25% solution must be mixed to produce 200mL of a 8% acid solution