0
What is the concentration of an AlCl3 solution if 150 ml of the solution contains 650 mg of Cl- ion?
Molarity = moles of solute/Liters of solution Atomic Mass of Cl- = 35.453 molecular mass = 35.453amu molar mass = 35.453g/mol moles = 650mgCl- X 1molCl-/35.453gCl- = 0.0183341325135molCl- 0.0183341325135molCl-/150ml = 0.12222755009 1.22X10-1M
What else can I help you with?
How many grams of sugar must be dissolved in 150 mL of water to make a solution that has a concentration of .6 g?
For a concentration of 0,6 g sugar/1000ml: 15 ml for 150 mL.
What is the concentration of a solution made by dissolving 20 g of KOH in 150 mL of water?
20 g/150 mL = 0.13 g/mL = 130 g/L
How many milliliters of a 0.266 m lino3 solution are required to make 150.0 ml of 0.075 m lino3 solution?
To find out how many milliliters of the 0.266 M LiNO3 solution are needed, you can use the formula C1V1 = C2V2, where C1 is the concentration of the first solution, V1 is the volume of the first solution, C2 is the concentration of the second solution, and V2 is the volume of the second solution. Plugging in the values, you can solve for V1, which will give you the volume of the 0.266 M LiNO3 solution needed to make 150.0 ml of 0.075 M LiNO3 solution.
How man meq of Na in 150ml of 0.9 percent NaCl?
There are 150 mg of Na in 1 ml of 0.9% NaCl solution. This is equivalent to 150 mEq of Na in 150 ml of the same solution.
What is a solution of salt and water contains 75 grams of water per 150 milliliters of the solutionIf 1 mole of water weight 16 grams what moles of water would be present in 30 milliliters of the solu?
In the given solution, there are 75 grams of water in 150 ml. This means there are 0.5 grams of water per milliliter. Therefore, in 30 ml of the solution, there would be 15 grams of water. To find the moles of water, divide the mass of water by its molar mass (16 g/mol), so in 30 ml of the solution, there would be 15/16 = 0.9375 moles of water present.
How many grams of sugar must be dissolved in 150 mL of water to make a solution that has a concentration of .6 g?
For a concentration of 0,6 g sugar/1000ml: 15 ml for 150 mL.
2.943g of pure sulphuric acid H2S4 is dissolved in water to make 150.0 cm3 of solution What is the concentration of the solution?
The concentration of a solution is moles/volume. 2.943g of pure sulphuric acid H2S4 is approximately 15 moles, and 15/150 cm3 is 10.
What is the concentration of a solution made by dissolving 20 g of KOH in 150 mL of water?
20 g/150 mL = 0.13 g/mL = 130 g/L
What is the minimum concentration of caffeine to take effect on reaction time?
A single cup of coffee contains 100-150 mg of caffeine.
How many ml 150 mg as in a injection?
The answer depends on the concentration of the solution being injected. You need to find the mg/ml number on the bottle to answer the question.
What is the molarity of NaCl concentration of blood?
The molarity of NaCl in blood is typically around 0.9%, which is equivalent to approximately 0.154 M. This concentration is close to the physiological concentration of sodium chloride in the body and is often used in medical settings as isotonic solution.
What is concentration of 150 gm of calcium carbonate in 850 ml of water?
Concentration is 150 gm solute per 850 mL solvent: 150 g solute per (150g + 850g =) 1000 g solution = 15% (m/m) CaCO3, since 850 mL is equal to (rounded) 850 grams.However calcium carbonate is rather INsoluble (smaller than 0.15 g/100 mL, about 0.15%) so this answer is physically impossible to achieve.If the question was mistyped and could have been 150 mg(= milligram, not gm = gram) per 850 mL, THEN the answer would have been 0.15 g per (850g + 0.15g =) 850 g solution which is (100%*0.15/850=) 0.018% CaCO3
What volume of stock solution would be required to make a 150 mL solution of 0.50 M HCl from a 2.00 M HCl stock solution?
To find the volume of the 2.00 M HCl stock solution needed, we use the formula M1V1 = M2V2. Rearranging for V1 gives us V1 = (M2 * V2) / M1, where M2 is the desired concentration (0.50 M), V2 is the final volume (150 mL), and M1 is the stock concentration (2.00 M). Plugging in the values gives V1 = (0.50 M * 150 mL) / 2.00 M = 37.5 mL. You will need 37.5 mL of the 2.00 M HCl stock solution to make a 150 mL solution of 0.50 M HCl.
What is the dosage given for the depo shot?
The three month Depo Provera shot has a concentration of 150 mg/1 ml. Each injection is 1 ml.
How many milliliters of a 0.266 m lino3 solution are required to make 150.0 ml of 0.075 m lino3 solution?
To find out how many milliliters of the 0.266 M LiNO3 solution are needed, you can use the formula C1V1 = C2V2, where C1 is the concentration of the first solution, V1 is the volume of the first solution, C2 is the concentration of the second solution, and V2 is the volume of the second solution. Plugging in the values, you can solve for V1, which will give you the volume of the 0.266 M LiNO3 solution needed to make 150.0 ml of 0.075 M LiNO3 solution.
How many grams of lidocaine are in 150 ml of a 2.5 M solution?
150 mL of a 2.5 M lidocaine solution contain 87,9 g.
How man meq of Na in 150ml of 0.9 percent NaCl?
There are 150 mg of Na in 1 ml of 0.9% NaCl solution. This is equivalent to 150 mEq of Na in 150 ml of the same solution.
