At the teperature above 1380 °C there are two product of this reaction: Na2O and SO3. At this temperature SO3 is unstable and decomposes to SO2 and 1/2 O2.
Na4Sn --> Na4 + Sn
sodium sulphate ( na2so4) it is a neutralisation reaction in which base + acid = salt + water it falls in the category of double decomposition reaction
Do you mean 2NaCl + H2SO4 → Na2SO4 + 2HCl ? This is a double decomposition (also known as double displacement) reaction. The hydrogen and sodium cations are switching their respective anions.
Na2SO4(s) --> 2Na+(aq) + SO4-2(aq)
H2SO4 + 2NaOH ------------> Na2SO4 + 2H2O H2SO4 + 2NaOH ------------> Na2SO4 + 2H2O H2SO4 + 2NaOH ------------> Na2SO4 + 2H2O
Na2SO4 and NaCl
sodium sulphate ( na2so4) it is a neutralisation reaction in which base + acid = salt + water it falls in the category of double decomposition reaction
First.Get moles sodium sulfate.5.35 grams Na2SO4 (1 mole Na2SO4/142.05 grams)= 0.0377 moles Na2SO4-------------------------------------Second.Molarity = moles of solute/Liters of solution ( 330 mL = 0.33 Liters )Molarity = 0.0377 moles Na2SO4/0.33 Liters= 0.114 M Na2SO4=============
25.0 grams Na2SO4 ( only way this compound is possible ) 25.0 grams Na2SO4 (1 mole Na2SO4/142.05 grams) = 0.176 moles Na2SO4 -----------------------------
Do you mean 2NaCl + H2SO4 → Na2SO4 + 2HCl ? This is a double decomposition (also known as double displacement) reaction. The hydrogen and sodium cations are switching their respective anions.
Na2SO4(s) --> 2Na+(aq) + SO4-2(aq)
H2SO4 + 2NaOH ------------> Na2SO4 + 2H2O H2SO4 + 2NaOH ------------> Na2SO4 + 2H2O H2SO4 + 2NaOH ------------> Na2SO4 + 2H2O
Because Na2SO4 is an ionic compound and so does not have actual molecules.
Na2SO4 and NaCl
Na2SO4 10.0 grams Na2SO4 (1 mole Na2SO4/142.05 grams)(2 mole Na/1 mole Na2SO4)(22.99 grams/1 mole Na) = 3.24 grams of sodium -------------------------------
inorganic
Na2SO4
8.20