At the teperature above 1380 °C there are two product of this reaction: Na2O and SO3. At this temperature SO3 is unstable and decomposes to SO2 and 1/2 O2.
Na2SO4.7H2O----------------Na2O + SO3 + 7 H2O
To find the molality, we first calculate the moles of Na2SO4: 10.0g Na2SO4 * (1 mol Na2SO4 / 142.04g Na2SO4) = 0.0705 moles Na2SO4. Then, molality is calculated as moles of solute (Na2SO4) / kilograms of solvent (water): 0.0705 mol / 1.000 kg = 0.0705 mol/kg, which is the molality of the solution.
Sodium sulfate.
When Na2SO4 dissolves in water, it dissociates into two Na+ ions and one SO4 2- ion. The dissociation equation is: Na2SO4 (s) -> 2Na+ (aq) + SO4 2- (aq).
The chemical formula for sodium sulfate is Na2SO4.
Na2SO4.7H2O----------------Na2O + SO3 + 7 H2O
To find the molality, we first calculate the moles of Na2SO4: 10.0g Na2SO4 * (1 mol Na2SO4 / 142.04g Na2SO4) = 0.0705 moles Na2SO4. Then, molality is calculated as moles of solute (Na2SO4) / kilograms of solvent (water): 0.0705 mol / 1.000 kg = 0.0705 mol/kg, which is the molality of the solution.
First.Get moles sodium sulfate.5.35 grams Na2SO4 (1 mole Na2SO4/142.05 grams)= 0.0377 moles Na2SO4-------------------------------------Second.Molarity = moles of solute/Liters of solution ( 330 mL = 0.33 Liters )Molarity = 0.0377 moles Na2SO4/0.33 Liters= 0.114 M Na2SO4=============
To find the mass of Na+ in sodium sulfate (Na2SO4), we need to consider the molar ratios of Na+ in the compound. In Na2SO4, there are 2 Na+ ions for every 1 Na2SO4 unit. The molar mass of Na2SO4 is 142 g/mol, so in 25 g of Na2SO4, there are about 8.8 g of Na+.
Sodium sulfate.
When Na2SO4 dissolves in water, it dissociates into two Na+ ions and one SO4 2- ion. The dissociation equation is: Na2SO4 (s) -> 2Na+ (aq) + SO4 2- (aq).
The chemical formula for sodium sulfate is Na2SO4.
The chemical formula for sodium sulfate is Na2SO4.
To find the number of moles of Na2SO4 in 25.0 g of the compound, you need to convert the mass to moles. First, determine the molar mass of Na2SO4, then divide the given mass by the molar mass to obtain the number of moles.
H2SO4 + 2NaOH ------------> Na2SO4 + 2H2O H2SO4 + 2NaOH ------------> Na2SO4 + 2H2O H2SO4 + 2NaOH ------------> Na2SO4 + 2H2O
inorganic
Na2SO4