25.0 grams Na2SO4 ( only way this compound is possible )
25.0 grams Na2SO4 (1 mole Na2SO4/142.05 grams)
= 0.176 moles Na2SO4
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5,7 moles (SO4)3-.
How many moles are in 4.70g of NH3?
For this you need the atomic (molecular) mass of Fe2(SO4)3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. Fe2(SO4)3=400.1 grams768 grams Fe2(SO4)3 / (400.1 grams) = 1.92 moles Fe2(SO4)3
This is Aluminum sulfate.
The moles number of water 12; the chemical formula is KAl(SO4)2.12H2O.
5,7 moles (SO4)3-.
To find the grams in 2.4 moles of SO4, you need to multiply the number of moles by the molar mass of SO4 (sulfate). The molar mass of SO4 is 96.06 g/mol. Therefore, 2.4 moles of SO4 would be 2.4 moles * 96.06 g/mol = 230.544 grams.
Al2 SO4(wrong) this is how it should be written Al2(SO4)3This how you do it3.5 moles Al2(SO4)3 x 3 mole Sulfur / 1 moles Al2(SO4)3 = put that in ur calculator it will give u the answer
There are 3 moles of sulfate ions (SO4^2-) present in 1 mole of Al2(SO4)3. Therefore, in 1.7 moles of Al2(SO4)3, there would be 3 * 1.7 = 5.1 moles of sulfate ions.
To calculate the number of grams in 1.11 moles of manganese sulfate (Mn3(SO4)7), you need to find the molar mass of the compound. The molar mass of Mn3(SO4)7 is approximately 678.88 g/mol. Therefore, 1.11 moles of Mn3(SO4)7 would be equal to 1.11 moles x 678.88 g/mol ≈ 753.38 grams.
SO4 is the chemical formula for the anion sulfate.
The molecular compound for sulfur tetroxide is SO4.
How many moles are in 4.70g of NH3?
Well...Since Aluminum is insoluble in water as an element I assume you mean that an 0.12 mol Aluminum ions react with 0.12 mol Sulfate ions to form x mol of Aluminum Sulfate. Balanced equation (Kinda since since the other portions of the compounds are unknown): 2 Al3+(aq) + 3 SO42-(aq) <----->Al2(SO4)3 (aq) 0.12mol*(1mol Al2(SO4)3 (aq)/2mol Al3+)=0.06mol Al2(SO4)3 (aq) 0.12mol*(1molAl2(SO4)3/3mol SO42-) =0.04mol Al2(SO4)3 (aq) *Answer*
Al2(SO4)3Aluminum Sulfate
The compound formula for ferric sulfate is Fe2(SO4)3.
SO4