Lugol's iodine is a mixture of elemental iodine and potassium iodide, commonly used as a disinfectant and as a supplement to support thyroid function. Gram's iodine, on the other hand, is a stain used in microbiology to differentiate between gram-positive and gram-negative bacteria based on their cell wall composition. The main difference lies in their applications and compositions.
To calculate the grams of iodine dissolved in water for 0.02 N iodine, you need the molar mass of iodine, which is approximately 254 g/mol. With this information, you can use the formula: Grams = Normality (N) * Equivalent weight. Therefore, for 0.02 N iodine: Grams = 0.02 * 254 = 5.08 grams of iodine.
For every 1 gram of zinc, 3.88 grams of iodine are required to react. So in this case, with 4.2 grams of zinc, the amount of iodine needed would be (4.2 grams zinc) * (3.88 grams iodine / 1 gram zinc) = 16.296 grams of iodine.
Iodine has a molar mass of 129.9g So one mol of Iodine is 129.9g. Therefore 10 moles of iodine would be 1299g.
Did you mean "What turns iodine into tincture of iodine?USP (U.S. National Formulary) Tincture of Iodine is defined as containing in each 100 mL, 1.8 to 2.2 grams of iodine, and 2.1 to 2.6 grams of sodium iodide. Alcohol is 50 ml and the balance is purified Water.
The density of iodine is 4,933 g/cm3 at room temperature.
Lugol's Iodine = 20g Potassium Iodide + 10g Iodine dissolved in 1L H2O Gram's Iodine = 6.7g potassium iodide + 3.3g Iodine dissolved in 1L H2O Recipe's taken from Flinn Scientific Catalog I have on campus. Looks to me as Gram's is just a dilute version of Lugol's. Same ratio of KI:I just less of it. Couldn't tell you much about differences in application however.
To calculate the grams of iodine dissolved in water for 0.02 N iodine, you need the molar mass of iodine, which is approximately 254 g/mol. With this information, you can use the formula: Grams = Normality (N) * Equivalent weight. Therefore, for 0.02 N iodine: Grams = 0.02 * 254 = 5.08 grams of iodine.
For every 1 gram of zinc, 3.88 grams of iodine are required to react. So in this case, with 4.2 grams of zinc, the amount of iodine needed would be (4.2 grams zinc) * (3.88 grams iodine / 1 gram zinc) = 16.296 grams of iodine.
222,6 grams of iodine is equivalent to 1,754 moles.
148 grams minus 125 grams is 23 grams.
Iodine has a molar mass of 129.9g So one mol of Iodine is 129.9g. Therefore 10 moles of iodine would be 1299g.
Iodine number is a measure of the relative unsaturation of a substance, typically a fat or oil. It indicates the amount of iodine in grams that can be absorbed by 100 grams of the substance, with higher numbers indicating a higher degree of unsaturation. This value is useful in determining the quality and stability of fats and oils for various industrial and nutritional applications.
It is the grams of iodine in a 0.1moldm^-3 solution of iodine
266g
Iron. It is there in grams. Iodine is there in milligrams.
Iodine is used to bind the Crystal Violet to the Gram Positive microbes.
Two ounces is equal to about 56.7 grams so it is about 50.7 grams heavier than six grams.