What is the empirical formula for C2H6O?

Answer 1

CH3O: When a molecular formula has a set of subscripts that can all be integrally divided by any integer other than one, division of the subscripts by the highest such integer will yield the empirical formula.

Answer 2

The empirical formula for a compound represents the simplest whole-number ratio of the elements present. To determine the empirical formula for C2H6O, we first need to find the greatest common factor for the subscripts of each element. In this case, the greatest common factor for C2H6O is 2, so the empirical formula simplifies to CH3O.

Answer 3

An empirical formula may be obtained from a molecular formula by dividing all of the subscripts in the formula by every common integral factor of all the subscripts until reaching a collection of subscript numbers that have no common integral factor except the number 1. In the given instance, the only common integral factor is 2; therefore, the empirical formula is CH3O.

Answer 4

C4H10 Empirical formula is C2H5.

To reduce a formula to its lowest empirical form, inspect the atom numbers.

See if the atom numbers have a common factor. In this case they do , which is '2' . So divide both atom numbers by '2' ; 4/2 = 2 and 10/2 = 5

So '2' & '5' take the formula to its lowest empirical form of C2H5 .

Answer 5

The empirical formula for C2H6O is CH3O. This can be determined by dividing each subscript in the molecular formula by the greatest common factor (in this case, 2).

Answer 6

It´s C2H4O

You divide it by the smallest number.

Answer 7

Dimethyl ether or ethanol.

Answer 8

C6H6O2is an empirical formula.

Answer 9

The empirical formula would be C4H5O3 as you can divide all the subscripts by 2 to get the lowest common factor.

Answer 10

it is C2H5O...