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What is the empirical formula of a compound that contains 59.9 percent titanium and 40.1 percent oxygen?
Wiki User
∙ 11y ago
Ti - atomic weight = 47.867
O - atomic weight = 16.0
59.9/47.867 = 1.25
40.1/16 = 2.50
2.50/1.25 = 2 therefore 1 Ti atom and 2 O atoms so TiO2
Wiki User
∙ 11y ago
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