This is called the ionization energy and an is different for each electron in the atom. Electrons in the outer shell (furthest from the nucleus) have the lowest ionization energy, electrons in the innermost shell (closest to the nucleus) have the highest ionization energy.
It depends on the element. If it is pretty unstable, it is easy to take away. If the element is really stable, like if it's a noble gas, it takes way more energy. It can also depend on the energy level. The bigger the energy level, the more energy it takes to take it away. For example, you don't need much energy to take away an electron from energy level 1, but it's REALLY hard to take an electron away from level 6.
The energy required to remove an electron from an atom is known as ionization energy. The ionization energy increases as the number of orbits around the nucleus increases.
What type of Atom?
I can not answer until I know which atom.
The energy needed to remove an electron from an atom (in the gaseous state) is called the IONIZATION ENERGY.
Ionization energy
Yes, this is the ionization energy.
Ionization energy.
The ionization energy
magnesium has a 2 valence electrons. because the third electron is not a valence electron, or in the outer shell, much more energy would be needed to remove it
In their outer electron shell, halogens have 7 valence electrons, one less than the number needed for a full shell. Therefore, it is much, much easier for the halogen to gain an electron in bonding than for it to lose 7 - the ionization energy (energy required to remove an electron from an atom) is quite high.
In their outer electron shell, halogens have 7 valence electrons, one less than the number needed for a full shell. Therefore, it is much, much easier for the halogen to gain an electron in bonding than for it to lose 7 - the ionization energy (energy required to remove an electron from an atom) is quite high.
Briefly, it is the energy required to completely remove a valence (outer shell) electron from its atom when forming an ionic bond.See related links below for more info
As the size of an atom increases, the energy needed to remove an electron decreases. As the size of an atom increases, the atomic radius increases: the distance between the nucleus and the outer electron shell becomes greater. This means that the positive nuclear charge has less of an effect on the negatively charged electron, so the attractive force between the nucleus and the electron is weaker. Less energy is required to overcome the weaker force.
magnesium has a 2 valence electrons. because the third electron is not a valence electron, or in the outer shell, much more energy would be needed to remove it
6 electrons
In their outer electron shell, halogens have 7 valence electrons, one less than the number needed for a full shell. Therefore, it is much, much easier for the halogen to gain an electron in bonding than for it to lose 7 - the ionization energy (energy required to remove an electron from an atom) is quite high.
In their outer electron shell, halogens have 7 valence electrons, one less than the number needed for a full shell. Therefore, it is much, much easier for the halogen to gain an electron in bonding than for it to lose 7 - the ionization energy (energy required to remove an electron from an atom) is quite high.
Briefly, it is the energy required to completely remove a valence (outer shell) electron from its atom when forming an ionic bond.See related links below for more info
Yes
Only 1 electron needed to make H stable.
As the size of an atom increases, the energy needed to remove an electron decreases. As the size of an atom increases, the atomic radius increases: the distance between the nucleus and the outer electron shell becomes greater. This means that the positive nuclear charge has less of an effect on the negatively charged electron, so the attractive force between the nucleus and the electron is weaker. Less energy is required to overcome the weaker force.
Ionization energy and electron affinity for cations and anions, respectively.
it is the energy required for a mole of atom to loose a mole of electron.
The Valence electron
Yes, it is correct.