I am actually very, very good at physics, and I am quite, very good at chemistry. So the Equation is:
Al + O = AlO2
The Answer is AlO2
The balanced equation for aluminum reacting with iron(II) oxide to produce aluminum oxide and iron is: 2Al + FeO -> Al2O3 + 2Fe.
The balanced equation for the reaction between aluminum and copper oxide is: 2Al + 3CuO → 3Cu + Al2O3. This reaction produces copper and aluminum oxide.
The balanced equation for the decomposition of aluminum oxide is: 2Al2O3(s) → 4Al(s) + 3O2(g)
The balanced equation for the reaction between aluminum and copper oxide is: 2Al + 3CuO -> 3Cu + Al2O3.
The word equation for aluminum forming its protective layer is: Aluminum + Oxygen → Aluminum oxide.
The balanced equation for aluminum reacting with iron(II) oxide to produce aluminum oxide and iron is: 2Al + FeO -> Al2O3 + 2Fe.
The balanced equation for the reaction between aluminum and copper oxide is: 2Al + 3CuO → 3Cu + Al2O3. This reaction produces copper and aluminum oxide.
The balanced equation for the decomposition of aluminum oxide is: 2Al2O3(s) → 4Al(s) + 3O2(g)
The balanced equation for the reaction between aluminum and copper oxide is: 2Al + 3CuO -> 3Cu + Al2O3.
The word equation for aluminum forming its protective layer is: Aluminum + Oxygen → Aluminum oxide.
The chemical equation 2Al2O3 represents the reaction of two aluminum atoms with three oxygen atoms to form two molecules of aluminum oxide. This equation shows that for every two moles of aluminum, three moles of oxygen are required to form two moles of aluminum oxide.
The unbalanced equation for the reaction of barium oxide (BaO), calcium oxide (CaO), and strontium oxide (SrO) with aluminum (Al) is: BaO + CaO + SrO + Al -> Ba + Ca + Sr + Al2O3
The balanced equation for the reaction between aluminum and iron (III) oxide to form aluminum oxide and iron is: 2Al + Fe2O3 → Al2O3 + 2Fe
2Al2O3 --> 4Al + 3O2
The chemical equation for the reaction between barium oxide, calcium oxide, and strontium oxide with aluminum is: 3BaO + 2Al → Al₂O₃ + 3Ba CaO + 2Al → Al₂O₃ + Ca SrO + 2Al → Al₂O₃ + Sr
The balanced chemical equation for the reaction between aluminum and oxygen to form aluminum oxide is: 4Al + 3O2 → 2Al2O3. From the balanced equation, we can see that 4 moles of aluminum react with 3 moles of oxygen to produce 2 moles of aluminum oxide. Therefore, if 3.40 mol of aluminum and 2.85 mol of oxygen are reacted, the limiting reactant is oxygen. Thus, 3.40 mol of aluminum would theoretically produce 1.90 mol of aluminum oxide.
The correct chemical equation is 4Al + 3O2 -> 2Al2O3, which represents the reaction where aluminum combines with oxygen gas to form aluminum oxide.