C2O4H2+H2SO4+5O=CO2+H2+SO4
Balance it by yourself if you can!
The equation for the reaction between hydrated oxalic acid (H2C2O4·2H2O) and sodium hydroxide (NaOH) is: H2C2O4·2H2O + 2NaOH → Na2C2O4 + 4H2O
The equation for the reaction between oxalic acid (H2C2O4) and sulfuric acid (H2SO4) is: H2C2O4 + H2SO4 → CO2 + H2O + SO2 + H2O
The balanced equation between potassium dichromate (K2Cr2O7) and oxalic acid (H2C2O4) is: K2Cr2O7 + 3H2C2O4 -> Cr2(C2O4)3 + 2K2C2O4 + 4H2O
Potassium Permanganate (KMnO4) reacts with Sulphuric acid (H2SO4) to produce Manganese Heptoxide (MnO7), water (H20) and Potassium Hydrogen Sulphate (KHSO4)2. The reactive species produced is Manganese Heptoxide (which is a very powerful oxidiser). The Manganese Heptoxide will oxidise the Oxalic acid (COOH)2 to Carbon dioxide (CO2).
The balanced equation for the reaction between oxalic acid (H2C2O4) and potassium permanganate (KMnO4) in acidic solution is: 5 H2C2O4 + 2 KMnO4 + 3 H2SO4 → 10 CO2 + 2 MnSO4 + 8 H2O + K2SO4
This titration is based on the neutralization reaction between oxalic acid and sulfuric acid; a pH indicator is used.
The equation for the reaction between hydrated oxalic acid (H2C2O4·2H2O) and sodium hydroxide (NaOH) is: H2C2O4·2H2O + 2NaOH → Na2C2O4 + 4H2O
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The equation for the reaction between oxalic acid (H2C2O4) and sulfuric acid (H2SO4) is: H2C2O4 + H2SO4 → CO2 + H2O + SO2 + H2O
The balanced equation between potassium dichromate (K2Cr2O7) and oxalic acid (H2C2O4) is: K2Cr2O7 + 3H2C2O4 -> Cr2(C2O4)3 + 2K2C2O4 + 4H2O
Potassium Permanganate (KMnO4) reacts with Sulphuric acid (H2SO4) to produce Manganese Heptoxide (MnO7), water (H20) and Potassium Hydrogen Sulphate (KHSO4)2. The reactive species produced is Manganese Heptoxide (which is a very powerful oxidiser). The Manganese Heptoxide will oxidise the Oxalic acid (COOH)2 to Carbon dioxide (CO2).
The balanced equation for the reaction between oxalic acid (H2C2O4) and potassium permanganate (KMnO4) in acidic solution is: 5 H2C2O4 + 2 KMnO4 + 3 H2SO4 → 10 CO2 + 2 MnSO4 + 8 H2O + K2SO4
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The equation for the decomposition of oxalic acid upon heating is: $2C_2H_2O_4 → 2CO_2 + 2H_2O + C_2O_2$ This reaction results in the formation of carbon dioxide, water, and carbon monoxide.
Well, when I looked online for the formula for oxalic acid, it said it was H2C2O4. If this is correct the equation would be H2C2O4 + Al(OH)3 --> H2O..... Something... Im not sure about that last part because the oxalic acid formula doesnt seem right to me... But it would be a double-displacement reaction.
When concentrated sulfuric acid is heated with oxalic acid, oxidation of oxalic acid takes place, giving off carbon dioxide gas and water as byproducts. This reaction can be used to generate carbon dioxide for various applications.
The reaction between NaOH and oxalic acid is a neutralization reaction, resulting in the formation of sodium oxalate and water. Oxalic acid is a dicarboxylic acid that can react with a base like NaOH to form a salt and water.