The equation for the reaction between ammonia and silver nitrate is:
2NH3 + AgNO3 → AgNH3 + NO3
No Reaction
Potassium nitrate is too stable and so is silver for these two species to react. There is thus no balanced equation.
The chemical equation is:Fe + 2 AgNO3 = Fe(NO3)2 + 2 Ag
Sodium chloride is a compound that fits this description. When sodium chloride reacts with silver nitrate solution, it forms a white precipitate of silver chloride. This precipitate is soluble in both aqueous ammonia and nitric acid.
the chemical equation for beryllium chloride reacts with silver nitrate in water to form beryllium nitrate and silver chloride can be written as follows .BeCl2 +2 Ag NO3 -> Be (NO3) 2 +2AgCl.A balanced equation has equal numbers of each type of atom on each side of the equation.
No Reaction
Potassium nitrate is too stable and so is silver for these two species to react. There is thus no balanced equation.
The chemical equation is: Na+I- (aq) + Ag+[NO3]- (aq) --> AgI (s) + Na+[NO3]- (aq)
The chemical equation is:Fe + 2 AgNO3 = Fe(NO3)2 + 2 Ag
Sodium chloride is a compound that fits this description. When sodium chloride reacts with silver nitrate solution, it forms a white precipitate of silver chloride. This precipitate is soluble in both aqueous ammonia and nitric acid.
the chemical equation for beryllium chloride reacts with silver nitrate in water to form beryllium nitrate and silver chloride can be written as follows .BeCl2 +2 Ag NO3 -> Be (NO3) 2 +2AgCl.A balanced equation has equal numbers of each type of atom on each side of the equation.
The reaction between Lysol and silver nitrate would yield a precipitate of silver chloride, as silver nitrate reacts with the chloride ions present in Lysol to form insoluble silver chloride. The balanced chemical equation for this reaction would be: AgNO3 + NaCl (from Lysol) → AgCl + NaNO3.
9.11 g
The balanced equation for this reaction is: 2 Na2S + 2 AgNO3 → Ag2S + 2 NaNO3
A double displacement reaction takes place, producing Silver Chloride and Nitric acid
When sodium iodide reacts with silver nitrate, a double displacement reaction occurs. The sodium ions exchange with the silver ions, forming silver iodide as a white precipitate and sodium nitrate. This reaction can be represented by the equation: 2NaI + 2AgNO3 → 2AgI + 2NaNO3
Mg(s) + 2AgNO3(aq) _> Mg(NO3)2(aq) + 2Ag(s)