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What is the grams of substance in 4.5 moles CaCO3?
Molar mass of CaCO3 = 66.1221g CaCO3/mole CaCO3. This means that 1 mole CaCO3 = 66.1221g CaCO3. To find the mass of 4.5 mole CaCO3, complete the following calculation: 4.5g CaCO3 X 1mol CaCO3/66.1221g CaCO3 = 0.068 mole CaCO3.
How many moles of CaCO3 is 73.4kg?
To find the number of moles in 73.4 kg of CaCO3, we first need to calculate the molar mass of CaCO3. The molar mass of CaCO3 is 100.09 g/mol. Converting 73.4 kg to grams gives 73,400 g. Dividing 73,400 g by the molar mass of CaCO3 gives approximately 733 moles.
Calculate the number of grams in these quantities 125kg CaCO3?
Just 125 kg of CaCO3 contains 125000 grams of the substance. I kilogram of any substance is equivalent to 1000 grams of it.
What is the equivalent weight of hydrogen per oxide?
The equivalent weight of hydrogen peroxide is 17 g/mol.
Equivalent weight of NaHPO4?
The equivalent weight of NaHPO4 is determined by calculating the molecular weight divided by the change in oxidation state per reacting equivalent. For NaHPO4, the molecular weight is 137.99 g/mol, and it can donate 1 equivalent of H+ or accept 1 equivalent of OH-. Therefore, the equivalent weight of NaHPO4 is 137.99 g/mol.
What is the concentration of the equivalent weight of a solution of 10 mgL of CaCO3?
The concentration is 10 mg/L.
What is the grams of substance in 4.5 moles CaCO3?
Molar mass of CaCO3 = 66.1221g CaCO3/mole CaCO3. This means that 1 mole CaCO3 = 66.1221g CaCO3. To find the mass of 4.5 mole CaCO3, complete the following calculation: 4.5g CaCO3 X 1mol CaCO3/66.1221g CaCO3 = 0.068 mole CaCO3.
How many moles of CaCO3 is 73.4kg?
To find the number of moles in 73.4 kg of CaCO3, we first need to calculate the molar mass of CaCO3. The molar mass of CaCO3 is 100.09 g/mol. Converting 73.4 kg to grams gives 73,400 g. Dividing 73,400 g by the molar mass of CaCO3 gives approximately 733 moles.
How much caco3 is required if you would like to produce 97.5 g cao?
To produce 97.5 g of CaO, you would need to start with the stoichiometrically equivalent amount of CaCO3. The molar mass of CaCO3 is 100.09 g/mol and CaO is 56.08 g/mol. Therefore, you would need 56.08 g of CaCO3 to produce 97.5 g of CaO.
Calculate the number of grams in these quantities 125kg CaCO3?
Just 125 kg of CaCO3 contains 125000 grams of the substance. I kilogram of any substance is equivalent to 1000 grams of it.
When a 1.25-gram sample of limestone was dissolved in acid 0.44 gram of CO2 was generated if the rock contained no carbonate other than CaCO3 what was the percent of CaCO3 by mass in the limestone?
CaCO3 +2HCl ------------> CaCl2 + CO2 + H2O number of moles of CO2 in .44 grams = .44/ 44 = .01 From equation it is clear that 1 mole of CO2 is produced from CaCO3 = 1 mole .01 mole of CO2 is formed from CaCO3 = .01 mole Weight of .01 mole of CaCO3 is = .01mole *100 g/mole = 1 gram weight % of CaCO3 is = 1*100/ 1.25 = 80 % w/w I've post my answer, so why don't you show that answer here with the question. It's fare. I must be informed about my answer weather it is right or wrong. Please inform me at amitmahalwar@yahoo.com
Formula of limestone?
It is CaCO3.....it is the same as marbleFormula: CaCO3
What is Equivalent weight of chlorine?
the equivalent weight of chlorine is 35.453, which is also it's atomic weight.
Is caco3 insoluble when react with water?
caco3 is solid form. its density is high so caco3 is not soluble in water. but co2 mix in water befuor the mix in caco3 . so caco3 is soluble after mixing the co2 .
What is the molecular weight for the mineral calcite?
The molecular weight for mineral calcite is 100.09. Calculated from the formula (Mol_Wt_Calc).
How do you balance CaCO3 ----- CaO CO2?
the answer is DECOMPOSITION... and that is the answer not CaCO3
What is CaCO3?
CaCO3 is the chemical formula for calcium carbonate.
