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Ionic product of water?

The ionic product of water, Kw, is the product of the concentrations of hydrogen ions (H+) and hydroxide ions (OH-) in water at a given temperature. It is a constant value at a given temperature, typically 25°C, and has a value of 1.0 x 10^-14 in pure water. Kw = [H+][OH-].


Why ionic product constant of water is temp dependent?

The ionic product constant of water, Kw, is temperature dependent because the dissociation of water into hydronium ions (H3O+) and hydroxide ions (OH-) is an endothermic reaction. As temperature increases, more water molecules dissociate into ions, leading to an increase in the concentration of H3O+ and OH- ions, thus affecting the value of Kw.


What is meant by ionic product of water?

The ionic product of water refers to the equilibrium constant for the dissociation of water into its ions, H+ and OH-. It is represented by the equation: Kw = [H+][OH-]. At 25°C, the value of Kw is 1.0 x 10^-14.


What is ionic product of water at 25 C?

The ionic product of water (Kw) at 25°C is 1.0 x 10^-14 mol^2/L^2. This value represents the equilibrium constant for the autoionization of water into hydronium (H3O+) and hydroxide (OH-) ions.


What is the ion-product constant for water?

The ionic product for water is defined byKW = [H3O+][OH-]For water at standard temperature and pressure, it is 1.00 x 10-14 mol2/dm6pKW (which is equivalent to the pH) will be 7 at room temperature,because it is the -log10 of KW, and -log10 of the square root of 1x10-14 is 7.

Related Questions

Ionic product of water?

The ionic product of water, Kw, is the product of the concentrations of hydrogen ions (H+) and hydroxide ions (OH-) in water at a given temperature. It is a constant value at a given temperature, typically 25°C, and has a value of 1.0 x 10^-14 in pure water. Kw = [H+][OH-].


Why ionic product constant of water is temp dependent?

The ionic product constant of water, Kw, is temperature dependent because the dissociation of water into hydronium ions (H3O+) and hydroxide ions (OH-) is an endothermic reaction. As temperature increases, more water molecules dissociate into ions, leading to an increase in the concentration of H3O+ and OH- ions, thus affecting the value of Kw.


What is meant by ionic product of water?

The ionic product of water refers to the equilibrium constant for the dissociation of water into its ions, H+ and OH-. It is represented by the equation: Kw = [H+][OH-]. At 25°C, the value of Kw is 1.0 x 10^-14.


What is ionic product of water at 25 C?

The ionic product of water (Kw) at 25°C is 1.0 x 10^-14 mol^2/L^2. This value represents the equilibrium constant for the autoionization of water into hydronium (H3O+) and hydroxide (OH-) ions.


What is the ion-product constant for water?

The ionic product for water is defined byKW = [H3O+][OH-]For water at standard temperature and pressure, it is 1.00 x 10-14 mol2/dm6pKW (which is equivalent to the pH) will be 7 at room temperature,because it is the -log10 of KW, and -log10 of the square root of 1x10-14 is 7.


Magnitude of kw indicates?

The magnitude of kw indicates the level of ionization in water. Kw is the ion product of water, which represents the concentration of hydroxide and hydronium ions in water at a given temperature. It is a measure of the strength of water as an acid and a base.


What is the pH range in hot water?

Can be anything, there's no strong link between pH and temperature. -------------- When the temperature is increasing the pH of water is decreasing and the ionic product (Kw) is increasing; at 50 0C the pH of pure water is 6,43. See the link below for the theory and for a table of pH.


How is Kw valid?

Kw is the ionisation constant for water at 25°C which value is 1.0x10^-14. (chemistry)In water at any pH the equilibrium state Kw is defined by and equal to the 'ion product':Kw = [H3O+]*[OH-] = 1.0*10-14at room temperature 25°C


What is water product?

Water product, often referred to in the context of chemistry and biology, typically refers to the product of the concentrations of hydrogen ions (H⁺) and hydroxide ions (OH⁻) in water, represented as Kw (the ion product of water). At 25°C, Kw is equal to 1.0 x 10⁻¹⁴, indicating the balance between the dissociation of water molecules into H⁺ and OH⁻ ions. This concept is essential in understanding acid-base chemistry and the pH scale.


What is the numerical value of Kw at 298 k?

The value of Kw (ion product of water) at 298 K is approximately 1.00 x 10^-14.


Prove that Kw equals product of Ka and Kb for an acid-base pair in water?

dissociation of acid in water: A + H2O <-> A- + H3O+ with dissociation constant Ka = [A-][H3O+]/[A][H2O] = [A-][H3O+]/[A]. dissociation of base in water: B + H2O <-> HB+ + OH- with dissociation constant Kb = [HB+][OH-]/[B][H2O] = [HB+][OH-]/[B] dissociation of water in itself: 2H2O <-> H3O+ + OH- with dissociation constant Kw = [H3O+][OH-]/[H2O]^2 = [H3O+][OH-] where [H2O] has been ommitted because it is a pure liquid. substituting relations for Ka and Kb into Kw gives: Kw = [H3O+][OH-] = (Ka[A]/[A-])(Kb[B]/[HB+]) = KaKb where [A] = [HB+] and [B] = [A-].


How is the Kw constant developed?

The Kw constant is derived from the auto-ionization of water, where water molecules can transfer a proton to each other to form hydronium and hydroxide ions. The equilibrium constant for this reaction is the Kw constant, which is the product of the concentrations of hydronium and hydroxide ions in water at a given temperature.