Weight and length cannot be associated without knowing other dimensions for the volume, or the density
To completely neutralize 100 ml of 1M H2SO4, you would need an equal number of moles of NaCl. H2SO4 is a diprotic acid, so you need 2 moles of NaCl for each mole of H2SO4. Therefore, you would need 2 moles of NaCl, which is equal to 117 grams (2 x molar mass of NaCl) to neutralize 100 ml of 1M H2SO4.
Use the equation Moles(m) = mass(g) / Mr (Relative Molecular Mass). To calculate the Mr , refer to the Periodic Table, for Atomic Masses. For H2SO4 We have H x 2 = 1 x 2 = 2 ( 1 is the atomic mass of H ) S x 1 = 32 x 1 = 32 ( 32 is the atomic mass of S). O x 4 = 16 x 4 = 64 (16 is the atomic mass of O). Adding 2 + 32 + 64 = 98 the Mr of H2SO4 Substituting into the eq'n above 1 mole = mass(g) / 98 Algebraic rearrangement mass(g) = 1 mole X 98(Mr) mass(g) = 98 grams. is the mass of 1 mole of H2SO4 .
No, 1M KOH (potassium hydroxide) does not equal 1M C7O2H7 (pimelic acid). They have different chemical formulas and properties, so their molarities cannot be equated in general chemical reactions or calculations.
To make a 0.1M solution from a 1M HCL solution, you would dilute the 1M HCL with 10 parts of water (or whatever solvent you are using). For example, mix 1 mL of 1M HCL with 9 mL of water to obtain a 0.1M HCL solution.
using the equation M1V1 = M2V2, V2 = M1V1/M2 = 1 x V/ 0.5 basically, whatever volume of 1M HCl you have, add the same mount of water and you will dilute it to 0.5M.
To completely neutralize 100 ml of 1M H2SO4, you would need an equal number of moles of NaCl. H2SO4 is a diprotic acid, so you need 2 moles of NaCl for each mole of H2SO4. Therefore, you would need 2 moles of NaCl, which is equal to 117 grams (2 x molar mass of NaCl) to neutralize 100 ml of 1M H2SO4.
You can not simply change from a measurement of volume to that of mass, for example if you had a 1m x 1m x 1m cube and filled it with lead, it would have a greater mass than if it were filled with air or wood.As such, in order to find the mass of an object of a given volume you are required to know what material the object is composed of, and hence it's density. Then it's mass can be calculated as below:Mass = Density x Volume
To answer this you need to find out the mass of 1m (or 1 dm) of nitrogen.
1m*1m*0.5m=0.5m3
the formula is no. moles is mass / molecular mass. As the number of moles is 1, the mass required will be exactly the same as the molecular mass, which is 58.32g
The formula for the area of a rectangle is A=LW; L- length and W- width. A=1m x 1m= 1m².
1m = 100 cmAnswer:77/100 of 1m
anything less then 1m?
1m
1m = 100cm 990cm/100cm/m = 9.9m 9.9m > 1m, so 990cm > 1m
1m x 1m = 1 square meter, or 1m squared.
anything less then 1m?