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How many moles HCl in 8.3 g HCl?
8.3 grams HCl (1 mole HCl/36.458 grams) = 0.23 moles HCl ------------------------
How many grams of HCl are contained in 4.25mL of a 0.405M aqueous solution of HCl?
M * V = n 0.405 M * 0.00425 ml = 0.00172125 mole of HCl The molar mass of HCl is: 1.007947 + 35.453 = 36.460947 g/mole m = mm * n So the mass in gram is: 36.460947 g/mole * 0.00172125 mole = 0.0628 gram
What is the mass of HCl that would be required to completely react with 5.2 grams of Mg?
The balanced chemical equation for the reaction between HCl and Mg is: Mg + 2HCl -> MgCl2 + H2. One mole of Mg reacts with 2 moles of HCl. Calculate the moles of Mg in 5.2 grams using the molar mass of Mg. Then use the mole ratio to find the moles of HCl needed, and finally calculate the mass of HCl using its molar mass.
What The Mass Of Hydrochloric Acid Reacts With 87.7 Grams Of Aluminum Dissolves In Excess Hydrochloric Acid?
The mass of hydrochloric acid needed to react with 87.7 grams of aluminum can be calculated using stoichiometry. The balanced chemical equation for the reaction between hydrochloric acid (HCl) and aluminum (Al) is 2Al + 6HCl → 2AlCl3 + 3H2. By applying stoichiometry, you'll find that the molar mass ratio between Al and HCl is 1:6. Therefore, the amount of HCl needed to react with 87.7 grams of Al is: (87.7 grams Al) x (6 moles HCl / 1 mole Al) x (36.46 g HCl / 1 mole HCl) = 151.63 grams of HCl.
Find out the mass of HCL needed to react completely with 0.20 g of ammonia gass?
Use grams to moles to moles to grams: 0.2 g of ammonia gas (NH3) is equivalent to 0.012 moles of NH3 (divide by 17g/mole) One mole of NH3 reacts with one mole of HCl: NH3 + HCl <=> NH4Cl So we need 0.012 moles of HCl to react with 0.012 moles of NH3 0.012 moles HCl * 36.5 g/mole HCl => 0.43 g HCl
How many moles HCl in 8.3 g HCl?
8.3 grams HCl (1 mole HCl/36.458 grams) = 0.23 moles HCl ------------------------
How many grams of HCl are contained in 4.25mL of a 0.405M aqueous solution of HCl?
M * V = n 0.405 M * 0.00425 ml = 0.00172125 mole of HCl The molar mass of HCl is: 1.007947 + 35.453 = 36.460947 g/mole m = mm * n So the mass in gram is: 36.460947 g/mole * 0.00172125 mole = 0.0628 gram
What is the mass of HCl that would be required to completely react with 5.2 grams of Mg?
The balanced chemical equation for the reaction between HCl and Mg is: Mg + 2HCl -> MgCl2 + H2. One mole of Mg reacts with 2 moles of HCl. Calculate the moles of Mg in 5.2 grams using the molar mass of Mg. Then use the mole ratio to find the moles of HCl needed, and finally calculate the mass of HCl using its molar mass.
What The Mass Of Hydrochloric Acid Reacts With 87.7 Grams Of Aluminum Dissolves In Excess Hydrochloric Acid?
The mass of hydrochloric acid needed to react with 87.7 grams of aluminum can be calculated using stoichiometry. The balanced chemical equation for the reaction between hydrochloric acid (HCl) and aluminum (Al) is 2Al + 6HCl → 2AlCl3 + 3H2. By applying stoichiometry, you'll find that the molar mass ratio between Al and HCl is 1:6. Therefore, the amount of HCl needed to react with 87.7 grams of Al is: (87.7 grams Al) x (6 moles HCl / 1 mole Al) x (36.46 g HCl / 1 mole HCl) = 151.63 grams of HCl.
Find out the mass of HCL needed to react completely with 0.20 g of ammonia gass?
Use grams to moles to moles to grams: 0.2 g of ammonia gas (NH3) is equivalent to 0.012 moles of NH3 (divide by 17g/mole) One mole of NH3 reacts with one mole of HCl: NH3 + HCl <=> NH4Cl So we need 0.012 moles of HCl to react with 0.012 moles of NH3 0.012 moles HCl * 36.5 g/mole HCl => 0.43 g HCl
How many grams are in 0.25 moles HCl?
To convert moles to grams, you need to know the molar mass of the substance. The molar mass of HCl is approximately 36.46 g/mol. Therefore, 0.25 moles of HCl would be equivalent to 9.115 grams (0.25 moles x 36.46 g/mol).
How many grams of zinc can react with 225ml of 0.200 m HCl solution?
Balanced equation first.Zn + 2HCl - ZnCl2 + H2now we find moles HCl by....Molarity = moles of solute/Liters of solution ( 225 ml = 0.225 Liters )0.200 M HCl = X moles/0.225 Liters= 0.045 moles HCl================Now, drive reaction backwards.0.045 moles HCl (1 mole Zn/2 mole HCl)(65.41 grams/1 mole Zn)= 1.47 grams zinc reacted----------------------------------
What is the molarity of a solution that contains 9.63 grams of HCl in 1.5 liters of solutions?
Molarity = moles of solute/Liters of solution Find moles NaCl 9 grams NaCl (1 mole NaCl/58.44 grams) = 0.154 moles NaCl Molarity = 0.154 moles NaCl/1 Liter = 0.2 M sodium chloride -------------------------------
How many grams of HCl are needed to obtain 1.0 liter of a 0.22 M HCl solution?
First.Molarity = moles of solute/Liters of solution0.22 M HCl = X moles/1.0 L= 0.22 moles HCl--------------------------Second.0.22 moles HCl (36.458 grams/1 mole HCl)= 8.0 grams hydrochloric acid needed===========================
How many moles are in 291.68 grams of hydrochloric acid?
To calculate moles of HCl in 291.68 grams, use the molar mass of HCl which is 1 + 35.5 = 36.5g/mole. 291.68 g x 1 mol/36.5 g = 7.99 moles HCl (3 sig figs)
How many moles are in 2 grams of HCL?
To find the number of moles in 2 grams of HCl, you need to divide the mass by the molar mass of HCl. The molar mass of HCl is approximately 36.46 g/mol. Therefore, 2 grams of HCl is equal to 2/36.46 = 0.055 moles.
What is the molality of a solution that contains 31.0 grams of HCl in 500 grams of water?
31 g of HCl divided by the molar mass of HCl to find how many mols. HCl --> H(1) + Cl(1) = molar mass of HCl 1.008(1) + 35.45(1)= 36.428 molar mass 31/36.428= 2.97 which is the mols of solute The mols of solute divided by kg of solute = molality 2.97/.500= 1.7 molality
