The mass of 4 moles of iron is 224 grams
4 mols Fe * 55.845(mass of iron)=223.38g
The number of moles is 4.
388.grams Fe divided by mass of Fe 388.2g/55.85= 6.95moles of Fe
To calculate the number of moles from grams, you must divide by the substance's molar mass
4 moles - APEX
The molecular mass of iron III nitrate is 241.86g/mol. Mass divided by molecular weight gives moles, which is 0.02481 moles (6/241.86)
The mass of 1.23 moles of iron is 58,69 g.
Molar mass of iron is 56g. Given mass of iron= 112g No. of moles = Given mass/Molar Mass => 112g/56g= 2 moles
The molar mass of iron is 55,845 g.Moles of iron = mass of iron/55,845
1 mole of iron atoms has the greatest mass - 55,845 g.
To determine the mass of Iron, its density is required. The formula used is Volume x Density = Mass. Assuming the Iron is pure and in solid state with a density of approximately 7.87g/cm3 at room temperature, its mass is around 51.2g.
If 85.65g of iron forms 118.37g of the oxide, the mass of oxygen combined with this mass of iron is 32.72g. Calculate the number of moles of iron and oxygen which have combined (after all, the formula of a compound shows the ratio of the number of moles of each element combined). Do this by dividing the mass reacted by the Relative Atomic Mass of the element concerned. i.e. For Iron it is 85.65/55.8 and for Oxygen 32.72/16. This gives a mole ratio of Fe:O as 1.53:2.04 or 3:4 Therefore the formula is Fe3O4
0.4965 moles rounded to 4 significant figures
The number of moles is 4.
388.grams Fe divided by mass of Fe 388.2g/55.85= 6.95moles of Fe
To calculate the number of moles from grams, you must divide by the substance's molar mass
4 moles - APEX
The molecular mass of iron III nitrate is 241.86g/mol. Mass divided by molecular weight gives moles, which is 0.02481 moles (6/241.86)