- oxygen: 51,43 %
- carbon: 42,09 %
- hydrogen: 6,48 %
The mass percentage of carbon in sucrose can be calculated by dividing the mass of carbon by the total mass of sucrose and then multiplying by 100. In this case, the mass percentage of carbon in sucrose would be (8.4 g / 20.0 g) x 100 = 42%.
To calculate the percentage of carbon in C17H19NO3, first find the molar mass of the compound which is the sum of the molar masses of each element. The molar mass of C17H19NO3 is approximately 285.31 g/mol. Then calculate the molar mass contributed by carbon (17 carbon atoms) which is about 12.01 g/mol per carbon atom. The total mass contributed by carbon is 17 * 12.01 = 204.17 g/mol. Finally, express this mass as a percentage of the total molar mass: (204.17/285.31) * 100% ≈ 71.53%. So, carbon represents approximately 71.53% of the mass in C17H19NO3.
The molecular mass of CO is 28. The carbon percentage by mass is ~43%. Hence the oxygen percentage by mass is ~57%.
This would depend on the isotopes of carbon and oxygen. Assuming that the most common isotopes are in play, use the atomic mass of each to get 2x (1) hydrogen + 2x (12.01) carbon + 2x (15.99) oxygen = roughly 58 (2x carbon)/58 = roughly 24/58 multiply (24/58) by 100 to get a percentage =41.379=41.38%
In terms of proportion of molecules that are carbon, 33% (formula: CO2 which means that there are 2 oxygens and 1 carbon). If you mean in terms of mass, then carbon is 27.27% of the molecule (Two oxygens at a molecular mass of 16 each, and one carbon at a molecular mass of 12) by mass.
Table sugar (sucrose) has a molecular formula of C12H22O11, which means it is composed of carbon, hydrogen, and oxygen. To calculate the percentage by mass of hydrogen in table sugar, divide the mass of hydrogen by the total mass of the compound and then multiply by 100. In this case, hydrogen has a total mass of 22 g/mol out of a total molecular mass of 342 g/mol, which gives a percentage of approximately 6.4% hydrogen by mass in table sugar.
To determine the percentage of the molar mass of N₂S₆ derived from carbon, we first note that N₂S₆ contains no carbon atoms. Therefore, the molar mass contribution from carbon is 0 grams. Consequently, the percentage of the molar mass of N₂S₆ derived from carbon is 0%.
There is no calcium in sugar. It contains only carbon, hydrogen and oxygen.
The mass percentage of carbon in sucrose can be calculated by dividing the mass of carbon by the total mass of sucrose and then multiplying by 100. In this case, the mass percentage of carbon in sucrose would be (8.4 g / 20.0 g) x 100 = 42%.
To calculate the percentage of carbon in C17H19NO3, first find the molar mass of the compound which is the sum of the molar masses of each element. The molar mass of C17H19NO3 is approximately 285.31 g/mol. Then calculate the molar mass contributed by carbon (17 carbon atoms) which is about 12.01 g/mol per carbon atom. The total mass contributed by carbon is 17 * 12.01 = 204.17 g/mol. Finally, express this mass as a percentage of the total molar mass: (204.17/285.31) * 100% ≈ 71.53%. So, carbon represents approximately 71.53% of the mass in C17H19NO3.
The molecular mass of CO is 28. The carbon percentage by mass is ~43%. Hence the oxygen percentage by mass is ~57%.
This would depend on the isotopes of carbon and oxygen. Assuming that the most common isotopes are in play, use the atomic mass of each to get 2x (1) hydrogen + 2x (12.01) carbon + 2x (15.99) oxygen = roughly 58 (2x carbon)/58 = roughly 24/58 multiply (24/58) by 100 to get a percentage =41.379=41.38%
The properly written formula, SiC, shows that the substance contains equal numbers of silicon and carbon atoms. Therefore, the atomic percentage of carbon is 50 %. The question may have been intended to ask for mass percentage. The gram atomic mass of silicon is 28.0855 and the gram atomic mas of carbon is 12.011. Therefore, the mass percentage of carbon is 100[12.011/(12.011 + 28.0855)] or about 29.956, to the justified number of significant digits.
In terms of proportion of molecules that are carbon, 33% (formula: CO2 which means that there are 2 oxygens and 1 carbon). If you mean in terms of mass, then carbon is 27.27% of the molecule (Two oxygens at a molecular mass of 16 each, and one carbon at a molecular mass of 12) by mass.
The molar mass of potassium carbonate (K2CO3) is 138.21 g/mol. The molar mass of carbon in K2CO3 is 12.01 g/mol. To find the percentage by mass of carbon, divide the molar mass of carbon by the molar mass of potassium carbonate and multiply by 100. This gives a percentage of approximately 8.69%.
To find the percent by mass of carbon in acetone (C3H6O), calculate the molar mass of carbon in acetone by adding the molar masses of the individual atoms: (3 × atomic mass of carbon) / molar mass of acetone × 100. This will give you the percentage of carbon in acetone by mass.
Among well-characterized compounds, lithium carbide probably contains the highest percentage of carbon by mass. However, it might well be possible to make a compound with more carbon by inducing one substitution on graphene or one of the other multi-atomic forms of carbon.