% K =2 x 39.1 x 100/ 138.2 =56.6
% C = 12 x 100/ 138.2 =8.68
% O = 3 x 16 x 100/ 138.2 =34.7
Potassium = 56.6 %
The relative formula mass of potassium carbonate (K2CO3) is 138.21 g/mol. This value is calculated by adding the atomic masses of each element in the compound: potassium (K) has a molar mass of 39.10 g/mol, carbon (C) has a molar mass of 12.01 g/mol, and oxygen (O) has a molar mass of 16.00 g/mol.
Heating copper carbonate causes it to decompose into copper oxide, carbon dioxide, and oxygen. When the carbon dioxide gas escapes, the overall mass of the compound decreases, resulting in a lower mass of copper carbonate after heating.
1,5 moles of potassium carbonate have 276,41 g.
The chemical equation for the decomposition of zinc carbonate is ZnCO3 → ZnO + CO2. From the equation, we see that 1 mole of zinc carbonate produces 1 mole of carbon dioxide. Zinc carbonate has a molar mass of 125.4 g/mol and carbon dioxide has a molar mass of 44.01 g/mol. By using stoichiometry, we can calculate that 125g of zinc carbonate produces 44.01g of carbon dioxide.
To calculate the percentage of calcium carbonate in the mixture, first find the total mass of the mixture by summing the individual masses given (1.05g + 0.69g + 1.82g = 3.56g). Then, calculate the percentage of calcium carbonate by dividing the mass of calcium carbonate by the total mass and multiplying by 100 (1.82g / 3.56g * 100 ≈ 51%). So, the percentage of calcium carbonate in the mixture is approximately 51%.
The relative formula mass of potassium carbonate (K2CO3) is 138.21 g/mol. This value is calculated by adding the atomic masses of each element in the compound: potassium (K) has a molar mass of 39.10 g/mol, carbon (C) has a molar mass of 12.01 g/mol, and oxygen (O) has a molar mass of 16.00 g/mol.
Heating copper carbonate causes it to decompose into copper oxide, carbon dioxide, and oxygen. When the carbon dioxide gas escapes, the overall mass of the compound decreases, resulting in a lower mass of copper carbonate after heating.
12 12.01
1,5 moles of potassium carbonate have 276,41 g.
The percentage by mass of sodium (Na) in a formula unit of sodium hydrogen carbonate (NaHCO3) is 27,38 %.
The chemical equation for the decomposition of zinc carbonate is ZnCO3 → ZnO + CO2. From the equation, we see that 1 mole of zinc carbonate produces 1 mole of carbon dioxide. Zinc carbonate has a molar mass of 125.4 g/mol and carbon dioxide has a molar mass of 44.01 g/mol. By using stoichiometry, we can calculate that 125g of zinc carbonate produces 44.01g of carbon dioxide.
To find the percentage of KCl in the mixture, we first need to determine the percentage of potassium coming from KCl. Since the mixture is 44.20% potassium by mass and KCl is 74.55% potassium by mass, we can set up a simple ratio to find the percentage of KCl in the mixture as (74.55% / 100%) * 44.20% = 32.97%. Therefore, the percentage of KCl in the mixture is approximately 32.97%.
To calculate the percentage of calcium carbonate in the mixture, first find the total mass of the mixture by summing the individual masses given (1.05g + 0.69g + 1.82g = 3.56g). Then, calculate the percentage of calcium carbonate by dividing the mass of calcium carbonate by the total mass and multiplying by 100 (1.82g / 3.56g * 100 ≈ 51%). So, the percentage of calcium carbonate in the mixture is approximately 51%.
Using stoichiometry, we can calculate the molar ratio between calcium carbonate and carbon dioxide. When 20g of calcium carbonate decompose to form 8.8g of carbon dioxide, the molar ratio is 1:1. Therefore, to produce 22g of carbon dioxide, you would need the same mass of calcium carbonate, which is 20g.
The percentage of iodine in potassium iodide can be calculated using the formula: (molar mass of iodine / molar mass of potassium iodide) x 100. The molar mass of iodine is approximately 126.9 g/mol, and the molar mass of potassium iodide is approximately 166 g/mol. Therefore, the percentage of iodine in potassium iodide is (126.9 / 166) x 100 = 76.5%.
30.115*10^23 molecules
The mass percentage of carbon in sucrose can be calculated by dividing the mass of carbon by the total mass of sucrose and then multiplying by 100. In this case, the mass percentage of carbon in sucrose would be (8.4 g / 20.0 g) x 100 = 42%.