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The formula for sodium carbonate us Na2CO3. Figure the molar mass of sodium carbonate to the nearest gram?
The molar mass of sodium carbonate to the nearest gram is 105,99 g.
What is the molar mass of aluminum carbonate to the nearest gram per mole?
To the nearest gram, molar mass of aluminium carbonate is 234 g/mol.
Molar mass of Iron 3 carbonate?
The molar mass of Iron(III) carbonate (Fe2(CO3)3) is calculated by adding the molar mass of iron (Fe) and three times the molar mass of carbonate (CO3). The molar mass of iron is approximately 55.85 g/mol, and the molar mass of carbonate is 60.01 g/mol. Therefore, the molar mass of Iron(III) carbonate is 291.88 g/mol.
What is the percent mass of calcium in a calcium supplement if 1.35-g of calcium carbonate is extracted from a 2.36-g pill?
The molar mass of calcium carbonate (CaCO3) is 100.09 g/mol. To calculate the percent mass of calcium, you need to divide the molar mass of calcium (40.08 g/mol) by the molar mass of calcium carbonate. This gives you a result of 0.4006, meaning that calcium constitutes approximately 40.06% of the mass of calcium carbonate.
What is the atomic number of carbonate?
carbonate isn't an element so therefore doesn't have an atomic number
How many moles of ions are there in 0.500g of carbonate ions?
To determine the number of moles of carbonate ions in 0.500g, you first need to calculate the molar mass of carbonate (CO3^-2). The molar mass of carbonate is 60.01 g/mol. Divide the given mass (0.500g) by the molar mass to find the number of moles. This will give you approximately 0.0083 moles of carbonate ions in 0.500g.
How many moles are in 4g of sodium carbonate?
To find the number of moles in 4g of sodium carbonate, first calculate the molar mass of sodium carbonate (Na2CO3), which is 105.99 g/mol. Then, divide the given mass by the molar mass to get the number of moles. Therefore, 4g of sodium carbonate is equivalent to approximately 0.038 moles.
How many moles of sodium carbonate are contained by 57.3g of sodium carbonate?
To find the number of moles of sodium carbonate in 57.3g, divide the given mass by the molar mass of sodium carbonate. The molar mass of sodium carbonate (Na2CO3) is 105.99 g/mol. Therefore, 57.3g / 105.99 g/mol = 0.54 mol of sodium carbonate.
How many moles of sodium carbonate were present in 2 grams of hydrated sodium carbonate?
To determine the number of moles of sodium carbonate in 2 grams of hydrated sodium carbonate, we first need to calculate the molar mass of Na2CO3·xH2O. Once we have the molar mass, we can use the formula: Moles = Mass / Molar mass. Given that hydrated sodium carbonate has the molar mass of Na2CO3·xH2O, we can determine the number of moles in 2 grams of the compound.
How many moles in 2.12g of sodium carbonate?
To find the number of moles in 2.12g of sodium carbonate, you first need to determine the molar mass of Na2CO3 (105.99 g/mol). Then, divide the given mass by the molar mass to get the number of moles. In this case, 2.12g / 105.99 g/mol ≈ 0.02 moles of sodium carbonate.
How many moles are in sodium carbonate?
To calculate the number of moles in sodium carbonate, you need to know the mass of the substance and its molar mass. Once you have the mass, divide it by the molar mass of sodium carbonate (105.99 g/mol) to find the number of moles. For example, if you have 10 grams of sodium carbonate, you would have 0.094 moles (10 g / 105.99 g/mol).
How many moles of sodium carbonate are present in 212g?
To calculate the number of moles of sodium carbonate in 212g, you need to first determine the molar mass of Na2CO3 (sodium carbonate). The molar mass of Na2CO3 is 105.99 g/mol. Then, you divide the given mass (212g) by the molar mass to find the number of moles (212g / 105.99 g/mol = 1.999 moles).
How many moles are there in 200 grams of Calcium Carbonate?
For a partly ionically bonded compound such as calcium carbonate, the gram formula mass is substituted for a mole, which technically exists only for purely covalently bonded compounds. The gram formula mass for calcium carbonate is 100.09. Therefore, 200 grams constitutes 200/100.09 or 2.00 gram formula masses of calcium carbonate, to the justified number of significant digits.
How many moles of ammonium ions are in 8.738 g of ammonium carbonate?
To determine the number of moles of ammonium ions in 8.738 g of ammonium carbonate, first calculate the molar mass of ammonium carbonate (NH4)2CO3. Then, divide the given mass by the molar mass to find the number of moles. Since there are two ammonium ions in one formula unit of ammonium carbonate, multiply the number of moles by 2 to get the moles of ammonium ions.
What is the mass in grams of 0.250 mol of the common antacid calcium carbonate?
The molar mass of calcium carbonate (CaCO3) is 100.09 g/mol. To find the mass of 0.250 mol of calcium carbonate, you would multiply the number of moles by the molar mass: 0.250 mol x 100.09 g/mol = 25.02 grams of calcium carbonate.
How many moles of ammonium ions does a 22.5 gram sample of ammonium carbonate?
To calculate the number of moles of ammonium ions in a 22.5 gram sample of ammonium carbonate, you need to first determine the molar mass of ammonium carbonate. Then, divide the given mass by the molar mass to find the number of moles. After that, since there are 2 ammonium ions in one molecule of ammonium carbonate, you will need to multiply the result by 2 to determine the number of moles of ammonium ions.
What is the mass of 0.5 moles of calcium carbonate (CaCO3)?
The molar mass of calcium carbonate (CaCO3) is approximately 100.09 g/mol. To find the mass of 0.5 moles of CaCO3, you would multiply the molar mass by the number of moles: 0.5 moles x 100.09 g/mol = 50.045 g. Therefore, the mass of 0.5 moles of calcium carbonate is 50.045 grams.
