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Solve for the masses of oxygen given 1 gram of Pb:

For PbO:

(1 g Pb)(1 mol Pb/207.2 g Pb)(1 PbO/1 Pb)(1 O/1 PbO)(16 g O/1 mol O) = 0.07722 g O

For PbO2:

(1 g Pb)(1 mol Pb/207.2 g Pb)(1 PbO2/1 Pb)(2 O/1 PbO2)(16 g O/1 mol O) = 0.1544 g O

For Pb2O3:

(1 g Pb)(1 mol Pb/207.2 g Pb)(1 Pb2O3/2 Pb)(3 O/1 Pb2O3)(16 g O/1 mol O) = 0.1158 g O

Get the ratio by dividing the smallest mass of oxygen to the rest of the calculated masses then multiply it by a certain factor to make it a whole number:

0.07722 / 0.07722 = 1 x 2 = 2

0.1544 / 0.07722 = 2 x 2 = 4

0.1158 / 0.07722 = 1.5 x 2 = 3

ANSWER: 2:4:3

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Q: What is the mass ratio of lead per gram of oxygen in the two compounds?
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