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The minimum photonic energy required to create an electron-positron pair is 1.022 MeV. This energy is the equivalent of the rest masses of the pair of particles created. There is a bit more to this, as conservation of momentum must be observed. Pair production will occur, when it occurs, in the vicinity of an atomic nucleus when a high energy gamma ray zips in. The nucleus provides some "help" to "balance the equations" that describe the event, and that atomic nucleus will allow symmetry to be preserved. Specifically, that atomic nucleus acts in the conservation of momentum. That's why pair production won't occur as gamma rays are flying through the vacuum of space; there are (virtually) no atoms out there to facilitate the event. It may sound complex, but it's not all that difficult to get a handle on the phenomenon. A link is provided to our friends at Wikipedia. Knowledge there is free, and pair production isn't all that tough to understand. The article is brief and readable, and the complex equations that might have been posted are absent. Check it out.

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16y ago

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Why you need 1.022 Mev in pair?

Pair production can only occur if the energy of the photon is bigger than the rest mass (E0 = m0*c^2) of electron and positron, because this is the energy needed to create these particle (conservation of energy). Excess energy will be kinetic energy of the electron and positron. Rest mass of electron and positron is 0.511 MeV each, so 1.022 MeV in total.


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