241.86 grams per mole
To determine the mass of iron(II) nitrate needed for 6.00 moles of Fe(NO3)2, you first need to calculate the molar mass of Fe(NO3)2. Fe(NO3)2 has a molar mass of approximately 179.86 g/mol. Therefore, the mass needed would be 6.00 moles * 179.86 g/mol ≈ 1079.16 grams of Fe(NO3)2.
Fe(NO3)2molecular weight. Molar mass of Fe(NO3)2= 179.8548 g/mol. This compound is also known as Iron(II) Nitrate. Convert grams Fe(NO3)2to moles or moles Fe(NO3)2to grams.
The molar mass of Pb(NO3)2 is calculated by adding up the atomic masses of each individual element in the compound. For Pb(NO3)2, the molar mass would be: Lead (Pb): 207.2 g/mol Nitrogen (N): 14.0 g/mol Oxygen (O): 16.0 g/mol Therefore, the molar mass of Pb(NO3)2 would be 207.2 + 2(14.0) + 6(16.0) = 331.2 g/mol.
I presume you mean 'Fe(NO3)3'. Note the use of brackets to indicate the number of nitrate anions. Otherwise the 'stand alone' suffix '3' is meaningless. Or wrongly confused as '33' oxygen atoms'. Note the use of Roman Numerals to indicate the oxidation state of iron. Fe(NO3)3 is Iron(III)nitrate or Ferric Nitrate. Molar Mass Fe x 1 = 56 x 1 = 56 N x 3 = 14 x 3 = 42 O x 3 x 3 = 16 x 9 = 144 56 + 42 + 144 = 242 (The molar mass). NB The 'N x 3' comes from the three nitrogen atoms, one each in the THREE nitrate anions. Similarly The 'O x 3 x 3 comes from three oxygen atoms, in each nitrate anion. There being three nitrate anions, means that there 3 x 3 = 9 oxygen atoms in the molecule. NNB Careful with the nomenclature. If there are only TWO nitrate anions present in the molecule , then the formula is 'Fe(NO3)2, and the name(s) are Iron(II)Nitrate or Ferrous Nitrate. NNNB 'Fe' is the chemical symbol for Iron. It comes from the Latin for Iron, which is 'Ferrum (Fe)'.
Fe(NO3)2 is an ionic compound. Iron (Fe) is a metal and nitrate (NO3) is a polyatomic ion, so together they form an ionic bond in Fe(NO3)2.
The molar mass of anhydrous iron(II) nitrate is 179,91 g.
To determine the mass of iron(II) nitrate needed for 6.00 moles of Fe(NO3)2, you first need to calculate the molar mass of Fe(NO3)2. Fe(NO3)2 has a molar mass of approximately 179.86 g/mol. Therefore, the mass needed would be 6.00 moles * 179.86 g/mol ≈ 1079.16 grams of Fe(NO3)2.
Fe(NO3)2molecular weight. Molar mass of Fe(NO3)2= 179.8548 g/mol. This compound is also known as Iron(II) Nitrate. Convert grams Fe(NO3)2to moles or moles Fe(NO3)2to grams.
Molar mass of Fe(NO3)2 is 55.85 + 2(14.00 + 3(16.00)) = 179.85 g/mol Therefore, number of moles of Fe(NO3)2 present is 53.55/179.85 = 0.2977 mol For each molecule of Fe(NO3)2, there are two atoms of nitrogen associated with it. Therefore, there are 0.2977*2 = 0.5954 mol of nitrogen atoms
The molar mass of Pb(NO3)2 is calculated by adding up the atomic masses of each individual element in the compound. For Pb(NO3)2, the molar mass would be: Lead (Pb): 207.2 g/mol Nitrogen (N): 14.0 g/mol Oxygen (O): 16.0 g/mol Therefore, the molar mass of Pb(NO3)2 would be 207.2 + 2(14.0) + 6(16.0) = 331.2 g/mol.
No, this statement is incorrect. The molar mass of CaCO3 (calcium carbonate) is 100.09 g/mol, while the molar mass of Ca(NO3)2 (calcium nitrate) is 164.08 g/mol. Therefore, the molar mass of Ca(NO3)2 is greater than that of CaCO3.
Iron nitrates are: - Fe(II)(NO3)2 - Fe(III)(NO3)3
I presume you mean 'Fe(NO3)3'. Note the use of brackets to indicate the number of nitrate anions. Otherwise the 'stand alone' suffix '3' is meaningless. Or wrongly confused as '33' oxygen atoms'. Note the use of Roman Numerals to indicate the oxidation state of iron. Fe(NO3)3 is Iron(III)nitrate or Ferric Nitrate. Molar Mass Fe x 1 = 56 x 1 = 56 N x 3 = 14 x 3 = 42 O x 3 x 3 = 16 x 9 = 144 56 + 42 + 144 = 242 (The molar mass). NB The 'N x 3' comes from the three nitrogen atoms, one each in the THREE nitrate anions. Similarly The 'O x 3 x 3 comes from three oxygen atoms, in each nitrate anion. There being three nitrate anions, means that there 3 x 3 = 9 oxygen atoms in the molecule. NNB Careful with the nomenclature. If there are only TWO nitrate anions present in the molecule , then the formula is 'Fe(NO3)2, and the name(s) are Iron(II)Nitrate or Ferrous Nitrate. NNNB 'Fe' is the chemical symbol for Iron. It comes from the Latin for Iron, which is 'Ferrum (Fe)'.
Fe(NO3)2 is an ionic compound. Iron (Fe) is a metal and nitrate (NO3) is a polyatomic ion, so together they form an ionic bond in Fe(NO3)2.
To find the molar mass of lead (II) nitrate (Pb(NO3)2), you first calculate the individual atomic masses of each element in the compound (Pb, N, O). Then, add up the atomic masses of each element based on the subscripts in the formula (2 nitrogens and 6 oxygens in this case) to get the molar mass. In this case, the molar mass of Pb(NO3)2 would be 331.2 g/mol.
To find the number of molecules in 122 grams of Cu(NO3)2, we need to first calculate the molar mass of Cu(NO3)2. The molar mass of Cu(NO3)2 is approximately 187.55 g/mol. Next, we convert the given mass to moles using the molar mass. Finally, we use Avogadro's number (6.022 x 10^23) to find the number of molecules, which would be approximately 3.25 x 10^22 molecules.
the equation would look like: 2(NO3) + Fe --> Fe(NO3)2 the 2 in front of the NO3 is there to balance the equation.