Molar mass of CaCO3 = 100.0869 g/mol
Molar mass of CaNO32 = 566.0655 g/mol
To answer this we must first find the molar mass of calcium carbonate. CaCO3Ca= 40.08gC=12.01gO= 16.00g (we have three oxygens so 16.00x3 is 48.00g)40.08+12.01+48.00= 100.09 gNow that we have the molar mass we can find how many grams there are:1.25 moles CaCo3 x (100.09 g CaCO3/ 1 mole CaCO3)= 125.11 grams CaCO3Therefore we'd have about 125 grams of CaCO3
For this you need the atomic (molecular) mass of CaCO3. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. CaCO3= 100.1 grams2.50 moles CaCO3 × (100.1 grams) = 250.25 grams CaCO3
molar mass CaCO3= 100g/m 100 x 0.250= 25 g
Atomic weight of carbon: [12,0096; 12,0116]. Atomic weight of chlorine: [35,446; 35,457]. The molar mass of chlorine is greater; rounded 35,45 g/mol.
3 mol CaCO3 will produce 3 mol CaO (and 3 mol CO2) on dry-heating. So 3 times the molar mass of CaO (56,1 g/mol) which is 168 g CaO
Molar mass of CaCO3 = 100.0869 g/mol
342.3
Molar mass of CaCO3 = 66.1221g CaCO3/mole CaCO3. This means that 1 mole CaCO3 = 66.1221g CaCO3. To find the mass of 4.5 mole CaCO3, complete the following calculation: 4.5g CaCO3 X 1mol CaCO3/66.1221g CaCO3 = 0.068 mole CaCO3.
The formula mass of calcium carbonate, CaCO3 is 40.1 + 12.0 + 3(16.0) = 100.1Note that 73.4kg is equivalent to 73400g.Amount of CaCO3 = mass of pure sample/molar mass = 73400/100.1 = 733molThere are 733 moles of calcium carbonate in a 73.4kg pure sample.
To answer this we must first find the molar mass of calcium carbonate. CaCO3Ca= 40.08gC=12.01gO= 16.00g (we have three oxygens so 16.00x3 is 48.00g)40.08+12.01+48.00= 100.09 gNow that we have the molar mass we can find how many grams there are:1.25 moles CaCo3 x (100.09 g CaCO3/ 1 mole CaCO3)= 125.11 grams CaCO3Therefore we'd have about 125 grams of CaCO3
CaCO3 is the formula of the substance (calcium carbonate), which gives the information about the proportions of the different elements which make up the compound. To find the 'mass percentage' however, it is necessary to use the molar mass of each element. Molar mass of Calcium = 40.08 g/mol Molar mass of Carbon = 12.01 g/mol Molar mass of Oxygen = 16.00 g/mol To find the percentage mass of one of these elements, divide the molar mass of the element by the total molar mass of the compound (add them all up, using oxygen three times), then multiply by 100%. Molar mass of CaCO3 = 40.08 +12.01 + 3*16.00 = 100.09 g/mol % Calcium = 40.08/100.09 * 100% = 40.0% % Carbon = 12.01/100.09 * 100% = 12.0% % Oxygen = (3*16.00)/10.09 * 100% = 48.0%
For this you need the atomic (molecular) mass of CaCO3. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. CaCO3= 100.1 grams2.50 moles CaCO3 × (100.1 grams) = 250.25 grams CaCO3
molar mass CaCO3= 100g/m 100 x 0.250= 25 g
gold, as it has a higher molar mass
Molar mass of CO2 is 44. Molar mass of NH3 is 17
Atomic weight of carbon: [12,0096; 12,0116]. Atomic weight of chlorine: [35,446; 35,457]. The molar mass of chlorine is greater; rounded 35,45 g/mol.
CaCO3, or calcium carbonate, has a molar mass of 100.09 grams per mole. This means there are roughly 566 grams of CaCO3.