CaCO3, or calcium carbonate, has a molar mass of 100.09 grams per mole. This means there are roughly 566 grams of CaCO3.
Molar mass of CaCO3 = 66.1221g CaCO3/mole CaCO3. This means that 1 mole CaCO3 = 66.1221g CaCO3. To find the mass of 4.5 mole CaCO3, complete the following calculation: 4.5g CaCO3 X 1mol CaCO3/66.1221g CaCO3 = 0.068 mole CaCO3.
250 grams CaCO3 (1 mole CaCO3/100.09 grams) = 2.50 moles of calcium carbonate
To calculate the number of moles in 27.50 grams of CaCO3, you need to divide the given mass by the molar mass of CaCO3. The molar mass of CaCO3 is approximately 100.09 g/mol. So, 27.50 grams divided by 100.09 g/mol gives you approximately 0.275 moles of CaCO3.
To convert moles to grams, you need to use the molar mass of calcium carbonate (CaCO3). The molar mass of CaCO3 is approximately 100.1 g/mol. To calculate the grams in 2.38 moles of CaCO3, you would multiply the number of moles (2.38) by the molar mass (100.1 g/mol), which gives you approximately 238 grams.
Assuming complete reaction, the molar mass of CaCO3 is approximately 100.09 g/mol. One mole of CaCO3 produces one mole of CO2. Therefore, 10 grams of CaCO3 will produce approximately 2.24 liters of CO2 at STP (22.4 L/mol).
Molar mass of CaCO3 = 66.1221g CaCO3/mole CaCO3. This means that 1 mole CaCO3 = 66.1221g CaCO3. To find the mass of 4.5 mole CaCO3, complete the following calculation: 4.5g CaCO3 X 1mol CaCO3/66.1221g CaCO3 = 0.068 mole CaCO3.
250 grams CaCO3 (1 mole CaCO3/100.09 grams) = 2.50 moles of calcium carbonate
To calculate the number of moles in 27.50 grams of CaCO3, you need to divide the given mass by the molar mass of CaCO3. The molar mass of CaCO3 is approximately 100.09 g/mol. So, 27.50 grams divided by 100.09 g/mol gives you approximately 0.275 moles of CaCO3.
For this you need the atomic (molecular) mass of CaCO3. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. CaCO3= 100.1 grams2.50 moles CaCO3 × (100.1 grams) = 250.25 grams CaCO3
The relative molecular mass of CaCO3 (calcium carbonate) is approximately 100.09 g/mol.
To convert moles to grams, you need to use the molar mass of calcium carbonate (CaCO3). The molar mass of CaCO3 is approximately 100.1 g/mol. To calculate the grams in 2.38 moles of CaCO3, you would multiply the number of moles (2.38) by the molar mass (100.1 g/mol), which gives you approximately 238 grams.
Assuming complete reaction, the molar mass of CaCO3 is approximately 100.09 g/mol. One mole of CaCO3 produces one mole of CO2. Therefore, 10 grams of CaCO3 will produce approximately 2.24 liters of CO2 at STP (22.4 L/mol).
The molar mass of calcium carbonate (CaCO3) is 100.09 g/mol. To find the mass of 0.250 mol of calcium carbonate, you would multiply the number of moles by the molar mass: 0.250 mol x 100.09 g/mol = 25.02 grams of calcium carbonate.
The amount of substance that will dissolve depends on the temperature and the solvent used. Thus, there is no way to tell how much will dissolve unless such a test is actually carried out (since that concentration of acid is not a standard solvent used in such experiments).
Using the molar mass of CaCO3 (100.09 g/mol), we find that 25g is equal to 0.249 mol. According to the balanced equation, 1 mol of CaCO3 produces 1 mol of CO2, so 0.249 mol of CaCO3 will produce 0.249 mol of CO2. Finally, using the molar mass of CO2 (44.01 g/mol), we determine that 0.249 mol of CO2 corresponds to 10.95 g.
Molar mass of CaCO3 = 100.0869 g/mol
The mass of sodium bicarbonate (NaHCO3) is 84 grams/mol, while the mass of calcium carbonate (CaCO3) is 100 grams/mol. Therefore, calcium carbonate has a higher molecular mass compared to sodium bicarbonate.