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What does the molar mass of C7H16 and the molar mass of CaCO3 have the same number of?
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∙ 12y ago
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∙ 12y ago
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What is the grams of substance in 4.5 moles CaCO3?
Molar mass of CaCO3 = 66.1221g CaCO3/mole CaCO3. This means that 1 mole CaCO3 = 66.1221g CaCO3. To find the mass of 4.5 mole CaCO3, complete the following calculation: 4.5g CaCO3 X 1mol CaCO3/66.1221g CaCO3 = 0.068 mole CaCO3.
How many moles of CaCO3 is 73.4kg?
The formula mass of calcium carbonate, CaCO3 is 40.1 + 12.0 + 3(16.0) = 100.1Note that 73.4kg is equivalent to 73400g.Amount of CaCO3 = mass of pure sample/molar mass = 73400/100.1 = 733molThere are 733 moles of calcium carbonate in a 73.4kg pure sample.
Calculate the number of moles in 27.50 grams CaCO3?
Approximally 0.275 moles. The molar mass of Ca C O3 is ~ 40+12+3*16 = 100g/mol 27.50g = x mol *100g/mol 27.50g/(100g/mol) = x mol 0.275 g/(g/mol) = x mol 0.275 mol = x mol
Molar mass of Li?
The molar mass of Li = 6.941 g/mol
Determine the mass of 21 mol N?
number of moles = mass/molar mass mass = number of moles x molar mass 21mol x 14gmol-1 = 294g molar mass of Nitrogen is 14, which you can find on a periodic table
The molar mass of CaCO3 is greater than the molar mass of CaNO32?
Molar mass of CaCO3 = 100.0869 g/molMolar mass of CaNO32 = 566.0655 g/mol
What is the mass of CaCO3?
Molar mass of CaCO3 = 100.0869 g/mol
What is the molar mass of C7H16?
'Exact' Mol mass of heptane, C7H16, (in 4 and 9 significant decimals):100.125200512 g mol−1
What is the grams of substance in 4.5 moles CaCO3?
Molar mass of CaCO3 = 66.1221g CaCO3/mole CaCO3. This means that 1 mole CaCO3 = 66.1221g CaCO3. To find the mass of 4.5 mole CaCO3, complete the following calculation: 4.5g CaCO3 X 1mol CaCO3/66.1221g CaCO3 = 0.068 mole CaCO3.
Calculate the mass in grams of 2.5 moles in calcium carbonate?
For this you need the atomic (molecular) mass of CaCO3. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. CaCO3= 100.1 grams2.50 moles CaCO3 × (100.1 grams) = 250.25 grams CaCO3
How many moles of CaCO3 is 73.4kg?
The formula mass of calcium carbonate, CaCO3 is 40.1 + 12.0 + 3(16.0) = 100.1Note that 73.4kg is equivalent to 73400g.Amount of CaCO3 = mass of pure sample/molar mass = 73400/100.1 = 733molThere are 733 moles of calcium carbonate in a 73.4kg pure sample.
What is molar mass a whole number multiple of?
Molar mass is a whole number multiple of the Empirical formula mass
Is avogadro's number the same as molar mass?
no youre thinking of molar mass and atomic weight although you use avogadro's number to find molar mass
How many grams are in 1.25 moles of calcium carbonate?
To answer this we must first find the molar mass of calcium carbonate. CaCO3Ca= 40.08gC=12.01gO= 16.00g (we have three oxygens so 16.00x3 is 48.00g)40.08+12.01+48.00= 100.09 gNow that we have the molar mass we can find how many grams there are:1.25 moles CaCo3 x (100.09 g CaCO3/ 1 mole CaCO3)= 125.11 grams CaCO3Therefore we'd have about 125 grams of CaCO3
Calculate the mass percent of each element in CaCO3?
CaCO3 is the formula of the substance (calcium carbonate), which gives the information about the proportions of the different elements which make up the compound. To find the 'mass percentage' however, it is necessary to use the molar mass of each element. Molar mass of Calcium = 40.08 g/mol Molar mass of Carbon = 12.01 g/mol Molar mass of Oxygen = 16.00 g/mol To find the percentage mass of one of these elements, divide the molar mass of the element by the total molar mass of the compound (add them all up, using oxygen three times), then multiply by 100%. Molar mass of CaCO3 = 40.08 +12.01 + 3*16.00 = 100.09 g/mol % Calcium = 40.08/100.09 * 100% = 40.0% % Carbon = 12.01/100.09 * 100% = 12.0% % Oxygen = (3*16.00)/10.09 * 100% = 48.0%
What is the mass in grams of 0.250 mol of the common antacid calcium carbonate?
molar mass CaCO3= 100g/m 100 x 0.250= 25 g
Calculate the number of moles in 27.50 grams CaCO3?
Approximally 0.275 moles. The molar mass of Ca C O3 is ~ 40+12+3*16 = 100g/mol 27.50g = x mol *100g/mol 27.50g/(100g/mol) = x mol 0.275 g/(g/mol) = x mol 0.275 mol = x mol
