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molar mass is the mass of one mole of a substance. A mole is an amount, refers to Avogadros number which is 6.022 x 1023. a mole of atoms is that many atoms. therefore the molar mass of potassium hydroxide KOH is the mass of that many molecules of KOH. On the Periodic Table the mass number for each element is molar, so all you need to do is add together the molar mass of each element in the compound. Molar mass of potassium (K) is 39 Molar mass of oxygen (O) is 16 Molar mass of hydrogen (H) is 1 There is one of each of these elements in a molecule of potassium hydroxide therefore the molar mass = 39 + 16 + 1 = 56
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How many moles are in 234.1 grams of KOH?
To find the number of moles in 234.1 grams of KOH, first calculate the molar mass of KOH (39.1 g/mol for K, 16.0 g/mol for O, and 1.0 g/mol for H). Add up the molar masses to get 56.1 g/mol for KOH. Divide the given mass (234.1 g) by the molar mass (56.1 g/mol) to find that there are approximately 4.17 moles of KOH in 234.1 grams.
How many moles are present in 34 grams of KOH?
To determine the number of moles in 34 grams of KOH, we first need to calculate its molar mass. The molar mass of KOH is approximately 56.11 g/mol (potassium: 39.10 g/mol, oxygen: 16.00 g/mol, hydrogen: 1.01 g/mol). Divide the given mass by the molar mass to find the number of moles: 34 g / 56.11 g/mol ≈ 0.61 moles of KOH.
How many moles of KOH are represented by 1.350g of KOH?
To calculate the number of moles of KOH, first find the molar mass of KOH which is 56.11 g/mol. Then, divide the given mass (1.350g) by the molar mass to get the number of moles. 1.350g / 56.11 g/mol = 0.024 moles of KOH.
What mass of potassium hydroxide is required to react completely with 2.70 g of sulfuric acid to produce potassium sulfate and water?
The balanced chemical equation for the reaction is: 2 KOH + H2SO4 -> K2SO4 + 2 H2O From the equation, it can be seen that 2 moles of KOH react with 1 mole of H2SO4. Calculate the moles of H2SO4 (2.70 g / molar mass of H2SO4) and then use the mole ratio to find the moles of KOH required. Finally, convert the moles of KOH to mass (moles of KOH x molar mass of KOH) to get the required mass of KOH.
What mass of KOH is needed to make 400mL of 725 M KOH?
I assume you mean 7.25 M KOH, but the process is the same anyway.Molarity = moles of solute/Liters of solution ( 400 ml = 0.4 Liters )7.25 M KOH = X moles KOH/0.4 Liters= 2.9 moles KOH (56.108 grams/1 mole KOH)= 163 grams potassium hydroxide needed===============================
How many moles are in 234.1 grams of KOH?
To find the number of moles in 234.1 grams of KOH, first calculate the molar mass of KOH (39.1 g/mol for K, 16.0 g/mol for O, and 1.0 g/mol for H). Add up the molar masses to get 56.1 g/mol for KOH. Divide the given mass (234.1 g) by the molar mass (56.1 g/mol) to find that there are approximately 4.17 moles of KOH in 234.1 grams.
How many moles are present in 34 grams of KOH?
To determine the number of moles in 34 grams of KOH, we first need to calculate its molar mass. The molar mass of KOH is approximately 56.11 g/mol (potassium: 39.10 g/mol, oxygen: 16.00 g/mol, hydrogen: 1.01 g/mol). Divide the given mass by the molar mass to find the number of moles: 34 g / 56.11 g/mol ≈ 0.61 moles of KOH.
How many moles of KOH are represented by 1.350g of KOH?
To calculate the number of moles of KOH, first find the molar mass of KOH which is 56.11 g/mol. Then, divide the given mass (1.350g) by the molar mass to get the number of moles. 1.350g / 56.11 g/mol = 0.024 moles of KOH.
What mass of potassium hydroxide is required to react completely with 2.70 g of sulfuric acid to produce potassium sulfate and water?
The balanced chemical equation for the reaction is: 2 KOH + H2SO4 -> K2SO4 + 2 H2O From the equation, it can be seen that 2 moles of KOH react with 1 mole of H2SO4. Calculate the moles of H2SO4 (2.70 g / molar mass of H2SO4) and then use the mole ratio to find the moles of KOH required. Finally, convert the moles of KOH to mass (moles of KOH x molar mass of KOH) to get the required mass of KOH.
What mass of KOH is needed to make 400mL of 725 M KOH?
I assume you mean 7.25 M KOH, but the process is the same anyway.Molarity = moles of solute/Liters of solution ( 400 ml = 0.4 Liters )7.25 M KOH = X moles KOH/0.4 Liters= 2.9 moles KOH (56.108 grams/1 mole KOH)= 163 grams potassium hydroxide needed===============================
What is the molarity of a solution that contains 112 grams of KOH in 2.00 liters of solution?
To find the molarity, first calculate the molar mass of KOH (56.11 g/mol for KOH). Next, divide the given mass of KOH (112 g) by its molar mass to get the number of moles. Finally, divide the moles of KOH by the volume of the solution in liters (2.00 L) to get the molarity. The molarity of the solution is 28.0 M.
How many grams of KOH and 4 g of H2?
To determine the number of grams of KOH, we first need to know the molar ratio between KOH and H2 in the balanced chemical equation. Once the molar ratio is determined, we can calculate the amount of KOH using stoichiometry. Without the molar ratio, we cannot determine the exact amount of KOH with just the information provided.
How would you make a 1.25 molar solution of potassium hydroxide?
To make a 1.25 M solution of potassium hydroxide, you would dissolve 5.0 grams of KOH in enough water to make 1 liter of solution. Start by calculating the molar mass of KOH (39.10 g/mol for K, 16.00 g/mol for O, and 1.01 g/mol for H), then use the formula Molarity (M) = moles of solute / liters of solution to determine the mass of KOH needed.
How many atoms are in 1 gram of KOH?
1 gram of KOH is equivalent to approximately (1.55 \times 10^{22}) atoms. This can be calculated by converting the mass of KOH to moles using its molar mass, and then using Avogadro's number (6.022 x 10^23) to determine the number of atoms in 1 mole of KOH (1 mole = 1 formula unit = 1 formula weight in grams).
What will be the molarity for a solution prepared by dissolving 50 grams of KOH in 700ml of water?
Molarity= Number of moles of solute/Liters of solution 50 grams KOH 700 ML to .7 Liters of h2o Molar Mass of KOH= 56 50 divided by 56 = .89 moles Molarity= .89 mol/.7 L = 1.27 MOLARITY
What is the molar mass of SiC?
Molar Mass of Carbon + Molar Mass of Silicon = Molar Mass of SiC. 12.0107 + 28.0855 = 40.0962 g / mol.
Calculate the number of grams of solute that would be needed to make 2.5 L of 0.800 M KOH?
0.800 M KOH (1mol/2.5L)(56.1g KOH/1mol)It's set up stoichiometrically, but hard to show that here... 0.800 M KOH / 2.5 L x 56.1gYour answer should come out 17.952 g KOH. If you're following sig figs, then your answer should come out 18. g KOH
