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0.800 M KOH (1mol/2.5L)(56.1g KOH/1mol)

It's set up stoichiometrically, but hard to show that here... 0.800 M KOH / 2.5 L x 56.1g

Your answer should come out 17.952 g KOH. If you're following sig figs, then your answer should come out 18. g KOH

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The answer is 14,0264 g KOH.

Q: Calculate the number of grams of solute that would be needed to make 2.5 L of 0.800 M KOH?

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PPM-Parts Per Million: Number of grams of solute per 1 million grams of solution. ppm=[mass of solute/mass of solution]*10 to the 6th power&PPB-Parts Per Billion: Number of grams of solute per 1 billion grams of solution.ppb=[mass of solute/mass of solution]*10 to the 9th power.Hope this helps.

grams and to calculate use a pan balance

The following solutions should be given so a person will be able to know how many grams of solute would be needed. With this information not given a person will not be able to know how much solute is needed.

200 grams of solution will contain 200 x 4% or 200 x 0.04 = 8.0 total grams of solute.

Yes

Related questions

In chemistry, parts per million or ppm is defined as the number of part of a solute that is in one million parts of a solution. The formula to calculate ppm is to divide the mass of the solute in grams by the combined mass of the solvent and solute also in grams. This value is multiplied by 1,000,000 ppm.

The molecular weight. So you'll have to calculate that for the solute first. The molar mass of the solute, which is measured in grams/mole.

Is the makeup of the solution expressed as "percent by mass"? If so, to calculate molarity (or normality), you have to also know the density of the solution Step 1. Lets say the solution is 14%, and the density is 1.09 g/mL. We can write the following: (14 grams solute/100 grams solution) (1.09 grams solution/ mL solution) Step 2. Multiplying and cancelling from step 1 gives you 15.26 grams solute / 100 mL solution. Multiplying top and bottom by 10 gives you 152.6 grams solute per liter. Step 3. Molarity is number of moles per liter. Divide the 152.6 grams of the solute by the forumua weight (or molecular weight) of the solute, and you have the number of moles of solute. This number is therefore the molarity of the solution. If the solution is "percent by volume", the number you have is number of grams per 100 mL. Multiply by 10, and you have grams per liter. Then divide by the formula weight, and you have the molarity.

The maximum number of grams of solute that can be dissolved in a given solvent is dependent on factors such as temperature, pressure, and the specific solute-solvent system. This maximum amount is known as the solubility limit of the solute in that particular solvent.

Calculate the molecular mass of the nonionic solutes. 8.02 grams of solute in 861 grams of water lower the freezing point to -0.430 ±C.

PPM-Parts Per Million: Number of grams of solute per 1 million grams of solution. ppm=[mass of solute/mass of solution]*10 to the 6th power&PPB-Parts Per Billion: Number of grams of solute per 1 billion grams of solution.ppb=[mass of solute/mass of solution]*10 to the 9th power.Hope this helps.

grams and to calculate use a pan balance

A measure of the amount of solute in a given amount of solvent. Where the units of concentration are grams of solute per milliter of solvent. ™ ~Ashna

Calculate the mass (in grams) of sodium sulfide that is needed to make 360ml of a 0.50 mol/L solution

Molality = moles of solute / kg of solvent solute = 44.9 grams of C10H8. There are approx 128 g/mole in C10H8. 44.9 grams x 1/128 moles/gram = 0.351 moles (approx) convert 175 grams C6H6 into 0.175 kilograms Molality = 0.351 moles solute (or C10H8) / 0.175 kg solvent (C6H6) Answer is 2.00 Molal

The answer is: Concentration can be expressed as grams of solute per milliliter of solvent.

The following solutions should be given so a person will be able to know how many grams of solute would be needed. With this information not given a person will not be able to know how much solute is needed.