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The formula for vanadium (II) phosphate is V3(PO4)2.
The molar mass of iron(II) sulfate (FeSO4) is 151.91 g/mol.
Because copper (II) cations have a charge of +2 and phosphate anions have a charge of -3, the formula of anhydrous* copper (II) phosphate is Cu3(PO4)2. This shows that each formula unit contains 2 atoms of phosphorus. Therefore, the atoms of phosphorus in 4.8 formula units is 4.8 x Avogadro's Number, or about 2.9 X 1024 atoms, to the justified number of significant digits. ____________________________________ The answer to the problem will be the same if hydrated copper (II) phosphate is assumed, because the water of hydration contains no phosphorus and the quantity is specified in moles or formula units, but the formula would be different.
The molar solubility of Iron (II) phosphate (Fe3(PO4)2) is about 1.4 x 10^-22 mol/L at 25°C. It is a sparingly soluble salt with a low solubility product constant.
To find the molar mass of copper (II) sulfate pentahydrate, calculate the individual molar masses of each element present (Cu, S, O, and H) from the periodic table, and then multiply by the respective subscript in the formula. Add up the molar masses of copper (II) sulfate (CuSO₄) and five water molecules (5H₂O) to get the molar mass of copper (II) sulfate pentahydrate.
The formula for vanadium (II) phosphate is V3(PO4)2.
The molar mass of iron(II) sulfate (FeSO4) is 151.91 g/mol.
The formula for the compounds: Chromium (VI) Phosphate; Vanadium (IV) Carbonate; Tin (II) Nitrite?
The molar mass of anhydrous iron(II) nitrate is 179,91 g.
Because copper (II) cations have a charge of +2 and phosphate anions have a charge of -3, the formula of anhydrous* copper (II) phosphate is Cu3(PO4)2. This shows that each formula unit contains 2 atoms of phosphorus. Therefore, the atoms of phosphorus in 4.8 formula units is 4.8 x Avogadro's Number, or about 2.9 X 1024 atoms, to the justified number of significant digits. ____________________________________ The answer to the problem will be the same if hydrated copper (II) phosphate is assumed, because the water of hydration contains no phosphorus and the quantity is specified in moles or formula units, but the formula would be different.
The molar solubility of Iron (II) phosphate (Fe3(PO4)2) is about 1.4 x 10^-22 mol/L at 25°C. It is a sparingly soluble salt with a low solubility product constant.
To find the molar mass of copper (II) sulfate pentahydrate, calculate the individual molar masses of each element present (Cu, S, O, and H) from the periodic table, and then multiply by the respective subscript in the formula. Add up the molar masses of copper (II) sulfate (CuSO₄) and five water molecules (5H₂O) to get the molar mass of copper (II) sulfate pentahydrate.
There are 2 forms of Copper(II) Sulphate, each with a different molar mass. * Copper(II) Sulphate Pentahydrate (CuSO4.5H20) This is the more common, blue, crystalline solid. it has a molar mass of: 249.7g mol-1 * Anhydrous Copper(II) Sulphate (CuSO4) This is less common to come across, it is a white powdery solid,and can be obtained by heating the pentahydrated form. Molar mass: 159.6g mol-1
The molar mass of NiSO4 (nickel(II) sulfate) is calculated by adding the atomic masses of each element present in the compound: Ni (nickel) has a molar mass of approximately 58.69 g/mol, S (sulfur) has a molar mass of approximately 32.06 g/mol, and O (oxygen) has a molar mass of approximately 16.00 g/mol. Therefore, the molar mass of NiSO4 is approximately 154.76 g/mol.
The molar mass of PbSO4 (lead(II) sulfate) is approximately 303.3 g/mol. This can be calculated by adding the molar masses of each element in the compound: lead (Pb) has a molar mass of 207.2 g/mol, sulfur (S) has a molar mass of 32.1 g/mol, and oxygen (O) has a molar mass of 16.0 g/mol.
The molar mass of iron(II) sulfate heptahydrate is 278,01556.
To find the mass of copper(II) nitrate, first calculate its molar mass: Cu(NO3)2 has a molar mass of approximately 187.56 g/mol. Then, multiply the molar mass by the number of moles to get the mass of 6.36 mol of copper(II) nitrate, which is approximately 1192.5 grams.