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What is the mass in grams of 3.52 mol of iron2 sulfate?
The formula for iron (II) sulfate is FeSO4.H2O, and its gram formula unit mass is 169.92. Therefore, 3.52 formula units of this compound have a mass of 598 grams, to the justified number of significant digits.
How do you calculate the molar mass of copper II sulfate pentahydrate?
To find the molar mass of copper (II) sulfate pentahydrate, calculate the individual molar masses of each element present (Cu, S, O, and H) from the periodic table, and then multiply by the respective subscript in the formula. Add up the molar masses of copper (II) sulfate (CuSO₄) and five water molecules (5H₂O) to get the molar mass of copper (II) sulfate pentahydrate.
How calculate the mass of iron 2 sulfate?
To calculate the mass of iron (II) sulfate (FeSO4), you would first find the atomic mass of each element (iron, sulfur, and oxygen) using the periodic table. Then, add the atomic masses of each element (Fe + S + 4O) to find the molar mass of FeSO4, which is approximately 151.91 g/mol. Finally, you can then calculate the mass of FeSO4 by multiplying the molar mass by the number of moles.
How many grams of copper(II) sulfate pentahydrate would you need to measure in order to have 10.0 grams of anhydrous copper (II) sulfate?
To calculate this, you would need to consider the molar masses of copper(II) sulfate pentahydrate and anhydrous copper(II) sulfate. Copper(II) sulfate pentahydrate has a molar mass that includes water molecules, so you need to determine the molar mass difference between the two compounds. Using this information, you can calculate the amount of copper(II) sulfate pentahydrate needed to obtain 10.0 grams of anhydrous copper(II) sulfate.
Find the molar mass of NiSO4?
The molar mass of NiSO4 (nickel(II) sulfate) is calculated by adding the atomic masses of each element present in the compound: Ni (nickel) has a molar mass of approximately 58.69 g/mol, S (sulfur) has a molar mass of approximately 32.06 g/mol, and O (oxygen) has a molar mass of approximately 16.00 g/mol. Therefore, the molar mass of NiSO4 is approximately 154.76 g/mol.
What is the calculation for the formula FeSO4.7H2O?
The molar mass of iron(II) sulfate heptahydrate is 278,01556.
What is the mass in grams of 3.52 mol of iron2 sulfate?
The formula for iron (II) sulfate is FeSO4.H2O, and its gram formula unit mass is 169.92. Therefore, 3.52 formula units of this compound have a mass of 598 grams, to the justified number of significant digits.
How do you calculate the molar mass of copper II sulfate pentahydrate?
To find the molar mass of copper (II) sulfate pentahydrate, calculate the individual molar masses of each element present (Cu, S, O, and H) from the periodic table, and then multiply by the respective subscript in the formula. Add up the molar masses of copper (II) sulfate (CuSO₄) and five water molecules (5H₂O) to get the molar mass of copper (II) sulfate pentahydrate.
How calculate the mass of iron 2 sulfate?
To calculate the mass of iron (II) sulfate (FeSO4), you would first find the atomic mass of each element (iron, sulfur, and oxygen) using the periodic table. Then, add the atomic masses of each element (Fe + S + 4O) to find the molar mass of FeSO4, which is approximately 151.91 g/mol. Finally, you can then calculate the mass of FeSO4 by multiplying the molar mass by the number of moles.
How many grams of copper(II) sulfate pentahydrate would you need to measure in order to have 10.0 grams of anhydrous copper (II) sulfate?
To calculate this, you would need to consider the molar masses of copper(II) sulfate pentahydrate and anhydrous copper(II) sulfate. Copper(II) sulfate pentahydrate has a molar mass that includes water molecules, so you need to determine the molar mass difference between the two compounds. Using this information, you can calculate the amount of copper(II) sulfate pentahydrate needed to obtain 10.0 grams of anhydrous copper(II) sulfate.
What is the molar mass of Fe(NO3)2?
The molar mass of anhydrous iron(II) nitrate is 179,91 g.
Yonas has 44.78 g of copper II sulfate How many moles does he have?
To find the number of moles of copper II sulfate Yonas has, you need to divide the given mass by the molar mass of the compound. The molar mass of copper II sulfate is 159.61 g/mol. 44.78 g / 159.61 g/mol = 0.281 moles of copper II sulfate.
What is chemical name for FeSO4?
Iron (II) sulfate is the correct name for this compound. The Fe ion has a charge of 2 and so does the sulfate ion, so there is no subscript after them.
Find the molar mass of NiSO4?
The molar mass of NiSO4 (nickel(II) sulfate) is calculated by adding the atomic masses of each element present in the compound: Ni (nickel) has a molar mass of approximately 58.69 g/mol, S (sulfur) has a molar mass of approximately 32.06 g/mol, and O (oxygen) has a molar mass of approximately 16.00 g/mol. Therefore, the molar mass of NiSO4 is approximately 154.76 g/mol.
What is the percent of iron in iron (II) hydroxide?
Iron (II) hydroxide has a chemical formula Fe(OH)2. To find the percent of iron in iron (II) hydroxide, you need to calculate the molar mass of iron (Fe) and divide it by the molar mass of the compound Fe(OH)2, then multiply by 100 to get the percentage. The percent of iron in iron (II) hydroxide is approximately 69.9%.
What are the individual ions in iron II sulfate?
The individual ions in FeSO4 (Iron II sulfate) are Fe2+ and SO42-.
How many S atoms are there in 120.0g of Copper(II)Sulfate?
There are 3 moles of S atoms in 120.0g of Copper(II) Sulfate. In one mole of Copper(II) Sulfate, there are 4 moles of oxygen atoms, 1 mole of sulfur atoms, and 1 mole of copper atoms. Since the molar mass of Copper(II) Sulfate is 159.61 g/mol, the molar mass of sulfur is 32.065 g/mol. Hence, there are 3 moles of sulfur atoms in 120.0g of Copper(II) Sulfate.
