To calculate the mass of iron (II) sulfate (FeSO4), you would first find the Atomic Mass of each element (iron, sulfur, and oxygen) using the Periodic Table. Then, add the atomic masses of each element (Fe + S + 4O) to find the molar mass of FeSO4, which is approximately 151.91 g/mol. Finally, you can then calculate the mass of FeSO4 by multiplying the molar mass by the number of moles.
To determine the number of moles of iron sulfate in 5.67g, you need to first calculate the molar mass of iron sulfate (FeSO4). The molar mass of FeSO4 is approximately 151.91 g/mol. Next, divide the given mass by the molar mass to find the number of moles. 5.67g / 151.91 g/mol ≈ 0.0373 moles of FeSO4.
In iron (III) sulfate, the ratio of iron to sulfate ions is 1:2. This means that for every one mole of iron (III) sulfate, there are three moles of sulfate ions. To find the number of sulfate ions in a 375.0 gram sample of iron (III) sulfate, you would first calculate the number of moles of iron (III) sulfate, and then multiply that by three to find the number of sulfate ions.
To calculate the mass in grams of sodium sulfate, we need to know the number of moles. Once we have the number of moles, we can multiply it by the molar mass to find the mass in grams. For example, if we have 2 moles of sodium sulfate, the mass would be 2 moles * 141.98 grams/mole = 283.96 grams.
The chemical formula for iron(II) sulfate is FeSO4.
The chemical formula for iron (II) sulfate is FeSO4.
To determine the number of moles of iron sulfate in 5.67g, you need to first calculate the molar mass of iron sulfate (FeSO4). The molar mass of FeSO4 is approximately 151.91 g/mol. Next, divide the given mass by the molar mass to find the number of moles. 5.67g / 151.91 g/mol ≈ 0.0373 moles of FeSO4.
In iron (III) sulfate, the ratio of iron to sulfate ions is 1:2. This means that for every one mole of iron (III) sulfate, there are three moles of sulfate ions. To find the number of sulfate ions in a 375.0 gram sample of iron (III) sulfate, you would first calculate the number of moles of iron (III) sulfate, and then multiply that by three to find the number of sulfate ions.
Iron (II) sulfate has iron in the +2 oxidation state, while iron (III) sulfate has iron in the +3 oxidation state. This means iron (II) sulfate has a lower charge on the iron ion compared to iron (III) sulfate, which affects its chemical properties and reactivity.
To find the moles of formula units in 5.67 g of iron III sulfate, you first need to calculate the molar mass of Fe2(SO4)3. The molar mass is 399.9 g/mol. Then, divide the given mass by the molar mass to find the number of moles. In this case, 5.67 g / 399.9 g/mol = 0.0142 moles of formula units.
To calculate the mass in grams of sodium sulfate, we need to know the number of moles. Once we have the number of moles, we can multiply it by the molar mass to find the mass in grams. For example, if we have 2 moles of sodium sulfate, the mass would be 2 moles * 141.98 grams/mole = 283.96 grams.
The chemical formula for iron(II) sulfate is FeSO4.
Iron (II) sulfate is the correct name for this compound. The Fe ion has a charge of 2 and so does the sulfate ion, so there is no subscript after them.
To calculate the number of moles in 112 g of iron, divide the given mass (112 g) by the molar mass of iron, which is approximately 55.85 g/mol. So, 112 g / 55.85 g/mol = approximately 2 moles of iron.
The chemical formula for iron (II) sulfate is FeSO4.
The individual ions in FeSO4 (Iron II sulfate) are Fe2+ and SO42-.
It would depend on your definition of percentage. For example, if you were looking for percentage of atom count, you would count the atoms in the compound Fe2(SO4)3. You have 12 Oxygen, 3 Sulfur, and 2 Iron, leaving you with 3 sulfur out of 17 total atoms, or 3/17 or 0.176470588 (about 17.5%). If, on the other hand, you are talking about percentage of mass, then you must calculate the mass of each element in the compound. Iron's atomic mass is 55.847. Sulfur's atomic mass is 32.066. Oxygen's atomic mass is 15.999. Multiply these by their respective ratios. Iron (55.847*2=111.694) Sulfur (32.066*3=96.198) Oxygen (15.999*12=191.988) Add them together to get (111.694+96.198+191.988=399.88) Now, take the overall mass of the sulfur part (96.198) and divide it into the total mass (399.88). The answer is 96.198/399.88 or 0.24056717 or about 24%.
The negative ion for iron sulfate is sulfate, which is made up of one sulfur atom and four oxygen atoms with a charge of -2. Iron sulfate has the chemical formula FeSO4.