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What is the molarity of 25.0 mL of 3.50 M HNO3 diluted to 0.250L?
Wiki User
∙ 11y ago
30 ml diluted to 250ml. 3.5 molar divided by 250 is 0.014. This multiplied by 30 is 0.42 molar.
Wiki User
∙ 10y ago
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How many milliliters of a stock solution of 11.1 m hno3 would be needed to prepare 0.500 l of 0.500 m hno3?
Use the equation; MaVa= MbVbWhere M is Molarity and V is volume.For this question, the left side of the equation is the information for 0.12M HNO3The unknown will be x on the right of the equation (replace Vb with x and solve for x).After the answer is found, it will need to be converted to mL, 1 L=1000mL
When 100. ml of when 100. ml of 0.125 m hcl is diluted to 250. ml the resulting molarity of the hcl solution i0.125 m hcl is diluted to 250. ml the resulting molarity of the hcl solution i?
Molarity = mole of solute/liter of solution. The unit for molarity is mol/L, and is abbreviated M or molar. Use the equation below, where M1 and M2 are molarity, and V1 and V2 are volume. The volumes given in mL must be converted to liters (L) by multiplying mL by 1 L/1000 mL. For example: 420 mL x 1 L/1000 mL = 0.420 L (The decimal is moved to the left three spaces.)M1V1 = M2V2, where M1=0.125 mol/L, V1=100. mL = 0.100. L, V2 = 250. mL = 0.250. L., M2 is unknown.Rearrange the equation to isolate M2. Plug in the known data and solve.M2 = (M1V1)/(V2)M2 = (0.125 mol/L x 0.100. L)/(0.250. L) = 0.05 mol/L = 0.050 M HCl
How many moles of CaCl2 are in 250 ml of CaCl2 solution?
It depends on the concentration of the solution. If you know the concentration(molarity) then use the equation. moles = [conc] x vol(mL) / 1000 NB The '1000' isusedto convert the concentration units of moles per litre (molL^-1) to mL.
What is the molarity of a solution prepared by combining 125 mL of 0.251 molar HCl with 250 mL of pure water?
0.0125
What will the pH of 250.0ml of aqueous containing 12.6g nitric acid?
HNO3 is nitric acid with a molecular weight of 63. So 126g would be 2 moles and hence 12.6g =0.2 moles. This is in 0.25 liters so the total molarity is 1000/250 x 0.2 = 0.8 molar. pH = - log10 [H+] so = -log10 0.8 = 0.097 or pH 0.1 rounded.
How many milliliters of a stock solution of 11.1 m hno3 would be needed to prepare 0.500 l of 0.500 m hno3?
Use the equation; MaVa= MbVbWhere M is Molarity and V is volume.For this question, the left side of the equation is the information for 0.12M HNO3The unknown will be x on the right of the equation (replace Vb with x and solve for x).After the answer is found, it will need to be converted to mL, 1 L=1000mL
When 100. ml of when 100. ml of 0.125 m hcl is diluted to 250. ml the resulting molarity of the hcl solution i0.125 m hcl is diluted to 250. ml the resulting molarity of the hcl solution i?
Molarity = mole of solute/liter of solution. The unit for molarity is mol/L, and is abbreviated M or molar. Use the equation below, where M1 and M2 are molarity, and V1 and V2 are volume. The volumes given in mL must be converted to liters (L) by multiplying mL by 1 L/1000 mL. For example: 420 mL x 1 L/1000 mL = 0.420 L (The decimal is moved to the left three spaces.)M1V1 = M2V2, where M1=0.125 mol/L, V1=100. mL = 0.100. L, V2 = 250. mL = 0.250. L., M2 is unknown.Rearrange the equation to isolate M2. Plug in the known data and solve.M2 = (M1V1)/(V2)M2 = (0.125 mol/L x 0.100. L)/(0.250. L) = 0.05 mol/L = 0.050 M HCl
How many moles of CaCl2 are in 250 ml of CaCl2 solution?
It depends on the concentration of the solution. If you know the concentration(molarity) then use the equation. moles = [conc] x vol(mL) / 1000 NB The '1000' isusedto convert the concentration units of moles per litre (molL^-1) to mL.
What is the molarity of a solution prepared by combining 125 mL of 0.251 molar HCl with 250 mL of pure water?
0.0125
What will the pH of 250.0ml of aqueous containing 12.6g nitric acid?
HNO3 is nitric acid with a molecular weight of 63. So 126g would be 2 moles and hence 12.6g =0.2 moles. This is in 0.25 liters so the total molarity is 1000/250 x 0.2 = 0.8 molar. pH = - log10 [H+] so = -log10 0.8 = 0.097 or pH 0.1 rounded.
What is the molarity of 80g magnesium chloride dissolved in 250ml of water?
MgCl2 Molarity = moles of solute/Liters of solution ( 250 ml = 0.250 L ) Get moles MgCl2 80 grams MgCl2 (1 mole MgCl2/95.21 grams) = 0.8402 moles MgCl2 Molarity = 0.8402 moles MgCl2/0.250 Liters = 3.4 M MgCl2 ----------------
you have 500 ml of a 1.5 m hcl solution (acid). if there is 250 ml of koh solution present (base). what will be the molarity of the koh (base)?
675
What is the number of moles of solute in 250 mL of a 0.4M solutionon centration?
1 mole in 250 ml and 4 moles in 1 liter or 1000 mls
What is the molarity of a solution containing .325 moles of solute in 250 ml of solution?
Given the eqaution c=n/v, where:c = concentrationn = number of molesv = volumeso, n=cv, that is: n = .25 X .4= 0.1 mol
How much 2M Nacl solution would you need to make 250ml of 0.15M Nacl solution?
By the definition of molarity, which is mass of solute in moles divided by solution volume in liters, 250 ml of 0.15 M NaCl* solution requires (250/1000)(0.15) or 0.0375 moles of NaCl. Each liter of 2M NaCl solution contains 2 moles of NaCl. Therefore, an amount of 0.0375 moles of NaCl is contained in (0.0375/2) liters, or about 18.75 ml of the 2M NaCl, and if this volume of the more concentrated solution is diluted to a total volume of 250 ml, a 0.15 M solution will be obtained. _________________ *Note correct capitalization of the formula.
What is the molarity of a solution that contains 0.65 moles of NaNO3 in 250 mL of solution?
Molarity (M) = moles of solute (mol) / liter of solution (L)M = mol / LYou have 250 mL of Solution, which is250 mL x ( 1 L / 1000 mL ) = ( 250 / 1000 ) L = .25 LSolute is just what's dissolvedSolvent is just what it's being dissolved inSolution is the solute and the solvent.M = mol / LM = 0.65 mol / 0.25 Liters = 2.6 mol/LThe two numbers that you are given, 0.65 moles and 250 mL both have two significant figures, and the answer is two significant figures (2.6 mol/L)Therefore the answer is 2.6 mol/L.
750 ml of 20M HCl is mixed with 250 ml of 60M HCl What is the new molarity?
Molarity of a solution is the number of moles of the solute divided by the volume of the solution (in liters). If 750 ml of 20M HCl is mixed with 250 ml of 60M HCl, we first find the total number of moles of HCl in our new solution. Using that same formula, M=moles/V, we cansee that moles=MV. In the first solution we have (20M)(0.750L) = 15 moles. In the second, (60M)(0.250L) = 15 moles, so we have a total of 30 moles in our new solution, which also has a volume of 750mL + 250mL = 1L. The molarity of the new solution is 30 moles/1L = 30M
