2.0 L x 0.60 mol/L = 1.2 moles NaOH
0.495 L x 3.0 mol/L = 1.485 moles NaOH
Total moles NaOH = 2.685 moles NaOH
Total volume = 2.0 L + 0.495 L = 2.495 L
Final concentration of NaOH = 2.685 moles/2.495 L = 1.076 M = 1.1 M (to 2 significant figures)
Determine the concentration of hydroxide ions by looking at the molarity of the base in the solution. A higher molarity of the base will result in a greater concentration of hydroxide ions. Use stoichiometry to calculate the concentration of hydroxide ions based on the balanced chemical equation for the reaction.
A 3 M sodium hydroxide solution means there are 3 moles of sodium hydroxide dissolved in 1 liter of solution.
The chemical formula for cobalt(II) hydroxide when it reacts with water to form a solution with a molarity of 0.63 M is Co(OH)2.
Molarity means moles per litre. So here you have to divide the moles by 75 and multiply by 1000. 0.5/75*1000, which is 6.667 molar.
The molarity of the potassium hydroxide solution is 3.30M. This can be calculated by determining the number of moles of sulfuric acid used (0.0171 mol), then equating this to twice the number of moles of potassium hydroxide used (0.00855 mol), and finally dividing this by the volume of the potassium hydroxide solution (0.00258 L).
Determine the concentration of hydroxide ions by looking at the molarity of the base in the solution. A higher molarity of the base will result in a greater concentration of hydroxide ions. Use stoichiometry to calculate the concentration of hydroxide ions based on the balanced chemical equation for the reaction.
The molarity is 0,125 M.
through molarity,molality, normality. through molarity,molality, normality.
Molarity:1.0 mol (NaOH) /L(solution) = 1.0 M NaOHThe conversions of molality, b, to and from the molarity , c,for one-solute solutions are:c = ρ.b / [1 + b.M]andb = c / [ρ -c.M]where ρ is the mass density of the solution, b is the molality, and M is the molar mass of the solute.
To calculate the normality of ammonium hydroxide (NH4OH), we need to know the molarity first. Once we have the molarity, we can determine the normality for NH4OH by accounting for the number of equivalents it can provide in a reaction. Normality is calculated as the molarity multiplied by the number of equivalents per molecule.
A 3 M sodium hydroxide solution means there are 3 moles of sodium hydroxide dissolved in 1 liter of solution.
To find the molarity of the barium hydroxide solution, first calculate the number of moles of hydrochloric acid used in the titration. Then use the stoichiometry of the reaction to determine the number of moles of barium hydroxide present. Finally, divide the moles of barium hydroxide by the volume of the solution in liters to get the molarity.
The chemical formula for cobalt(II) hydroxide when it reacts with water to form a solution with a molarity of 0.63 M is Co(OH)2.
Molarity = moles of solute/Liters of solution ( 1500 mL = 1.5 Liters ) Molarity = 0.800 moles NaOH/1.5 Liters = 0.533 M sodium hydroxide ...
.13 (Plato)
By dissolving the same number of moles of each substance in the same volume of water
Molarity means moles per litre. So here you have to divide the moles by 75 and multiply by 1000. 0.5/75*1000, which is 6.667 molar.