2.0 L x 0.60 mol/L = 1.2 moles NaOH
0.495 L x 3.0 mol/L = 1.485 moles NaOH
Total moles NaOH = 2.685 moles NaOH
Total volume = 2.0 L + 0.495 L = 2.495 L
Final concentration of NaOH = 2.685 moles/2.495 L = 1.076 M = 1.1 M (to 2 significant figures)
1.1
answer 1.1
80
Ffss
Molarity = Moles/Unit VolumeSo here Molarity = (0.0255) / (10-2) = 2.55 M
Yes, and for many solutions it often is.
Factor in hcl ?
Molarity or Molality
The concentration of the OH- is 8.0 x 10-4 In terms of molarity, since the hydroxide is double that of the calcium, double the molarity of the solution.
The molarity is 0,125 M.
through molarity,molality, normality. through molarity,molality, normality.
It depends on the molarity of the solution
The 1 molarity of Na-OH, or sodium hydroxide, is a solution that contains 1 mole of sodium hydroxide per liter of solution. It is commonly used as a strong base in various chemical reactions and titrations.
(100ml)(0.125M NaOH) = (500ml)(X Molarity) Molarity = 0.025 M
Molarity = Moles/Unit VolumeSo here Molarity = (0.0255) / (10-2) = 2.55 M
4m
Yes, and for many solutions it often is.
Factor in hcl ?
Molarity = moles of solute/Liters of solution ( 1500 mL = 1.5 Liters ) Molarity = 0.800 moles NaOH/1.5 Liters = 0.533 M sodium hydroxide ...
.13 (Plato)
Molarity or Molality