Molarity:
1.0 mol (NaOH) /L(solution) = 1.0 M NaOH
The conversions of molality, b, to and from the molarity , c,
for one-solute solutions are:
c = ρ.b / [1 + b.M]
and
b = c / [ρ -c.M]
where ρ is the mass density of the solution, b is the molality, and M is the molar mass of the solute.
This depends on the mass of NaOH dissolved in 1 L water.
1620 ml = 1.62 Liters Molarity = moles of solute/Liters of solution Molarity = 2 moles NaOH/1.62 Liters = 1 M NaOH solution ===============
I assume you mean 32.0 grams of NaOH and 450 milliliters of NaOH. Molarity = moles of solute/Liters of solution ( 450 ml = 0.450 liters ) get moles of NaOH 32.0 grams NaOH (1 mole NaOH/39.998 grams) = 0.800 moles NaOH Molarity = 0.800 moles NaOH/0.450 liters = 1.78 Molar NaOH
95g NaOH * 1 mol NaOH/ = 2.375 mol NaOH 40g NaOH Molarity (M) = mol / L M = (2.375) / (0.450) M = 5.28
Molarity = moles of solute/Liters of solutionMolarity = 4 moles NaOH/ 2L= 2 M NaOH========
Molarity = moles of solute/Liters of solution Molarity = 2.5 moles NaOH/10 Liters = 0.25 M NaOH ==========
Need moles sodium hydroxide first.80 grams NaOH (1 mole NaOH/39.998 grams) = 2.000 moles NaOHMolarity = moles of solute/Liters of solutionMolality = 2.000 moles NaOH/1 liter= 2 M NaOH solution===============
Molarity = moles of solute/volume of solution 2.24 grams NaOH (1mol/33.998g) = 0.0659 moles NaOH/0.5 liters = 0.132 Molarity of NaOH
.75 L because you multiply the L of NaOH by the Molarity of NaOH the divide it by the Molarity given of NaOH to get the volume needed
(100ml)(0.125M NaOH) = (500ml)(X Molarity) Molarity = 0.025 M
to prepare 1N we have to dilute 40gms of NaOH in 1 litre of water as for NaOH normality =molarity so to prepare 0.1N NaOH we have to dilute 4gms of NaOH in 1 litre of water..
80g of NaOH dissolved in 250ml. of water find the molarity of this solution ?
Molarity = moles of solute/Liters of solutionLiters of solution = moles of solute/MolarityLiters NaOH = 3.25 moles NaOH/2.5 M NaOH= 1.30 Liters NaOH=============
Since each NaOH molecule contains only one hydroxide ion, the normality of NaOH is equal to its molarity. Therefore, 1.0 N of NaOH is the same as 1 M.
Molarity is a measure of concentration. As an example, 1M NaOH solution contains 40g of NaOH in one litre of water (1000g) and thus the concentration would be 4% NaOH.
Molarity = moles of solute/Liters of solution 0.343 M NaOH = moles NaOH.2.5 Liters = 0.8575 moles NaOH (39.998 grams/1 mole NaOH) = 34 grams of NaOH ----------------------------
The answer is 0,625 moles.
The molarity is 0,33.
Add .4 grams solid NaOH to 1 liter of water. Molarity is moles per liter. Since the molar mass of NaOH is 40g/mol, a 1 M solution of NaOH would be 40 g (1 mole of NaOH) in 1 liter. One thousandth of this is .4 grams, giving 1 mM.
Can find moles this way. Molarity = moles of solute/Liters of solution ( 500 ml = 0.500 Liters ) 1 M NaOH = moles NaOH/0.500 Liters = 0.5 moles NaOH (39.998 grams/1 mole NaOH) = 19.999 grams NaOH needed ( call it 20 grams )
- log(0.048 M NaOH) = 1.3 pH --------------need Molarity? 1/10 1.3 = 0.050 M H3O ---------------------
40 g NaOH in 1 liter is 1 molar. So 400 mg = 0.4 g in 100 ml = 4 g per liter and thus 0.1 molar.
Molarity = moles of solute/Liters of solution. ( 350 ml = 0.350 Liters ) 5.7 M NaOH = moles NaOH/0.350 Liters = 1.995 moles NaOH (39.998 grams/1 mole NaOH) = 78 grams NaOH needed ------------------------------------
Molarity = moles of solute/Liters of solution ( 24.5 mL = 0.0245 L)Rearranged,moles of solute = Liters of solution * MolarityMoles NaOH = (0.0245 L)(0.130 M NaOH)= 3.19 X 10 -3 moles NaOH==================