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C8h18

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2013-05-30 15:40:57
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Q: What is the molecular formula of a compound with an empirical formula of C4H9 and a gram formula mass of 114 grams mole?
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What is the molecular formula of a compound with the empirical formula P2O5 and a gram-molecular mass of 284 grams?

the answer is: P4O10


What is the molecular formula for a compound with empirical formula CH2O and molar mass of 180.2 grams per mole?

C6h12o6


What is the molecular formula of a compound that has an empirical formula of c2oh4 and a molar mass of 88 grams per mole?

C4O2H8


What is the molecular formula of a compound with the empirical formula CH and a molar mass of 39.01 grams per mole?

C3h3


What is the molecular formula of a compound with an empirical formula of C2OH4 and a molar mass of 88 grams per mole?

This compound may be dioxane - C4H8O2.


What is its molecular formula if the molar mass of the compound is 199.55 grams per mole?

Cannot answer this question without knowing the EMPIRICAL formula.


What is the molecular formula of a compound given the molar mass of the compound is 162.27 grams and the empirical formula is C2H3?

The gram formula unit mass of the empirical formula C2H3 is twice the gram atomic mass of carbon plus three times the gram atomic mass of hydrogen, or about 27. The nearest integer to 162.27/27 is 6. Therefore, the molecular formula for the compound is C12H18.


How do you calculate the molecular formula of a substance which contain 80 percent C and 20 percent H?

You can only calculate the empirical formula because you do not have a mass of this compound given. To do the empirical formula assume 100 grams and change percent to grams. Get moles. 80 grams Carbon (1 mole C/12.01 grams) = 6.66 moles C 20 grams hydrogen (1 mole H/1.008 grams) = 19.84 moles H the smallest becomes 1 in the empirical formula and the other number is divided by it, Thus; H/C 19.84 moles H/6.66 moles C = 2.9, which we call 3 so, CH3 --------------- is the empirical formula To get the molecular formula tour question needed to read; How to calculate molecular formula from such ans such mass of compound with these percentages of elements, Which, of course, your question did not provide. Then you would have divided that given mass by the mass total of the elements of the empirical formula, got a whole number by which you would have multiplied the numbers of your empirical formula to get molecular formula.


What steps are used to convert an empirical formula into a molecular formula?

A molecular formula is the same as or a multiple of the empirical formula. The first step will be to assume exactly 100 grams of the substance, then convert each of these masses to moles,


What is the molecular formula of fructose with C 40 percent H 6.72 percent O 53.28 percent?

We assume 100 grams and turn those percentages into grams and find moles of species. 40 grams carbon (1 mole C/12.01 grams) = 3.33 moles C 6.72 grams hydrogen (1 mole H/1.008 grams) = 6.67 moles H 53.28 grams oxygen (1 mole O/16 grams) = 3.33 The smallest mole number is 1, so we have two small numbers. Divide the large number by the small. 6.67/3/33 = 2 so.............. CH2O is the empirical formula. You did not state that you had a quantity of this compound ( such as 60 grams, or whatever ), so the molecular formula can not be found from this info. C6H12O6 is of course the molecular formula. To find the molecular formula you need a mass of the compound aside from the simple percentages. Then you find, as we have done, the empirical formula. you divide the mass given by the mass of the empirical formula and then take that quotient and multiply it times the empirical formula. In this case (CH2O) * 6 = C6H12O6, the molecular formula


A compound is composed of 85.64 percent carbon and 14.36 percent hydrogen The compound has a formula mass of 42.08 grams What is the molecular formula?

The molecular formula is C3h6.


If a compound has an empirical formula of CH and a mass of 26 grams what is the molecular formula?

First, add together the atomic masses of the elements:C- 12.0H- 1.00_______13.0Now put it into the following formula:x(added atomic mass) = molecular weight13.0x = 26.0Then find xx= 2Take the x value and multiply it with the number of atoms in the empirical formula/C1H1 * 2 = C2H2The final answer is the actual molecular formula C2H2 or Acetylene

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