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To determine the molecular formula from the empirical formula and gram formula mass, first calculate the empirical formula mass of C4H9 (4 carbons + 9 hydrogens). Then, divide the gram formula mass by the empirical formula mass to find the ratio. Finally, multiply the subscripts in the empirical formula by this ratio to get the molecular formula, which in this case is C8H18.

Q: What is the molecular formula of a compound with an empirical formula of C4H9 and a gram formula mass of 114 grams mole?

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molar mass over grams of elementThe above answer is somewhat correct. In order to find the molecular formula when given the empirical formula, you must first find the molar mass of the empirical formula.MOLAR MASS# atoms element A x Atomic Mass element A (Periodic Table) = mass A# atoms element B x atomic mass element B (periodic table) = mass B... etc.Add up all of the mass values found above and you have the molar mass.Then, after you have found the empirical formula's molar mass, you divide the molar mass of the molecular formula by the empirical formula's molar mass (solving for n).MOLECULAR FORMULA EQUATION: N (Empirical formula) (read as N times empirical formula) where:N = Molar mass substance---- Molar Mass emp. form.

To find the molecular formula, you need to know the empirical formula and the molar mass of the compound. First, calculate the empirical formula mass of C2H3 = 2(12.01) + 3(1.01) = 27.05 g/mol. Then, divide the molar mass by the empirical formula mass to get the ratio of 162.27 g/mol / 27.05 g/mol = 6. Using this ratio, the molecular formula would be C12H18.

In addition to the percent by mass of each element, you also need the molar mass of each element. This information allows you to convert the percent by mass into grams and then into moles, which is necessary to determine the empirical formula and subsequently the molecular formula of the compound.

Yes, the empirical formula is based on the relative number of atoms in a compound, so it will remain the same regardless of the masses used to determine it. The empirical formula represents the simplest ratio of elements in a compound.

Say you have 100 grams of the compound. If so, then you would have 3.1 grams H, 31.5 grams P, and 65.4 grams O. Convert these to moles: 3.1 grams H Ã· 1.01 grams/mol = 3.07 moles H 31.5 grams P Ã· 31.0 grams/mol = 1.02 moles P 65.4 grams O Ã· 16.0 grams/mol = 4.09 moles O Divide each of these by the smallest number, which is 1.02: 3.07 Ã· 1.02 = 3 1.02 Ã· 1.02 = 1 4.09 Ã· 1.02 = 4 These are your ratios. The empirical formula is then H3PO4

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Cannot answer this question without knowing the EMPIRICAL formula.

By determining the molecular mass, then dividing the molecular mass by the formula mass of the empirical formula to determine by what integer the subscripts in the empirical formula must be multiplied to produce the molecular formula with the experimentally determined molecular mass.

The empirical formula C2OH4 simplifies to C1O2H2. To find the molecular formula, divide the molar mass (88 g/mol) by the empirical formula mass (112 + 216 + 2*1 = 46 g/mol) to get 1.91. This means the molecular formula is approximately 1.91 times the empirical formula, so the molecular formula is C2O4H4.

You can only calculate the empirical formula because you do not have a mass of this compound given. To do the empirical formula assume 100 grams and change percent to grams. Get moles. 80 grams Carbon (1 mole C/12.01 grams) = 6.66 moles C 20 grams hydrogen (1 mole H/1.008 grams) = 19.84 moles H the smallest becomes 1 in the empirical formula and the other number is divided by it, Thus; H/C 19.84 moles H/6.66 moles C = 2.9, which we call 3 so, CH3 --------------- is the empirical formula To get the molecular formula tour question needed to read; How to calculate molecular formula from such ans such mass of compound with these percentages of elements, Which, of course, your question did not provide. Then you would have divided that given mass by the mass total of the elements of the empirical formula, got a whole number by which you would have multiplied the numbers of your empirical formula to get molecular formula.

The empirical formula of C2H5 corresponds to an empirical mass of 29 g/mol. To find the molecular formula from the empirical formula and molecular mass, divide the molecular mass by the empirical mass to get the "scaling factor" (58 g/mol รท 29 g/mol = 2). Multiply the subscripts in the empirical formula by the scaling factor to get the molecular formula: C2H5 x 2 = C4H10. So, the molecular formula is C4H10.

We assume 100 grams and turn those percentages into grams and find moles of species. 40 grams carbon (1 mole C/12.01 grams) = 3.33 moles C 6.72 grams hydrogen (1 mole H/1.008 grams) = 6.67 moles H 53.28 grams oxygen (1 mole O/16 grams) = 3.33 The smallest mole number is 1, so we have two small numbers. Divide the large number by the small. 6.67/3/33 = 2 so.............. CH2O is the empirical formula. You did not state that you had a quantity of this compound ( such as 60 grams, or whatever ), so the molecular formula can not be found from this info. C6H12O6 is of course the molecular formula. To find the molecular formula you need a mass of the compound aside from the simple percentages. Then you find, as we have done, the empirical formula. you divide the mass given by the mass of the empirical formula and then take that quotient and multiply it times the empirical formula. In this case (CH2O) * 6 = C6H12O6, the molecular formula

molar mass over grams of elementThe above answer is somewhat correct. In order to find the molecular formula when given the empirical formula, you must first find the molar mass of the empirical formula.MOLAR MASS# atoms element A x Atomic Mass element A (Periodic Table) = mass A# atoms element B x atomic mass element B (periodic table) = mass B... etc.Add up all of the mass values found above and you have the molar mass.Then, after you have found the empirical formula's molar mass, you divide the molar mass of the molecular formula by the empirical formula's molar mass (solving for n).MOLECULAR FORMULA EQUATION: N (Empirical formula) (read as N times empirical formula) where:N = Molar mass substance---- Molar Mass emp. form.

To find the molecular formula, you need to know the empirical formula and the molar mass of the compound. First, calculate the empirical formula mass of C2H3 = 2(12.01) + 3(1.01) = 27.05 g/mol. Then, divide the molar mass by the empirical formula mass to get the ratio of 162.27 g/mol / 27.05 g/mol = 6. Using this ratio, the molecular formula would be C12H18.

To find the molecular formula, you need the empirical formula and molar mass. If the molar mass is 160 plus 5 grams per mole, the molecular formula cannot be determined without additional information about the empirical formula's molar mass relationship.

The formula of NO2 has a molecular weight of 46 g/mol. Your compound has a molecular weight of 92 g/mol. As you can see the molecular weight of the compound is twice that of the empirical formula. Therefore the molecular formula of your compound is:2 *(NO2) ---> N2O4

To find the molecular formula from percentage composition, you would first convert the percentages to grams. Then, divide the mass of each element by its molar mass to find the moles. Finally, divide the moles by the smallest number of moles calculated to get the empirical formula, which can then be used to determine the molecular formula if the molar mass of the compound is known.

In addition to the percent by mass of each element, you also need the molar mass of each element. This information allows you to convert the percent by mass into grams and then into moles, which is necessary to determine the empirical formula and subsequently the molecular formula of the compound.