If C2H5 was the molecular formula its molecular mass would be 29 ( 12 x 2 + 5 x 1)
However, 29 x 2 = 58 the actual molecular mass. So we double up the atoms in C2H5 to C4H10 . C4H10 is the molecular formula.
By determining the molecular mass, then dividing the molecular mass by the formula mass of the empirical formula to determine by what integer the subscripts in the empirical formula must be multiplied to produce the molecular formula with the experimentally determined molecular mass.
Cannot answer this question without knowing the EMPIRICAL formula.
Well, darling, to find the empirical formula, you need to convert the grams of each element to moles. Then, you divide the moles of each element by the smallest number of moles calculated. In this case, the empirical formula would be CH3. Happy calculating, sugar!
To calculate parts per million (ppm) from molecular weight, you first need to know the mass of the substance in grams per mole. Then, you can use the formula: ppm = (mass of substance in grams / total mass of mixture in grams) * 10^6. This will give you the concentration of the substance in parts per million.
Dicyclohexyl chemical formula is C12H22 and the molecular weight is 166,3031 (not 200).
To find the molecular formula, you need the empirical formula and molar mass. If the molar mass is 160 plus 5 grams per mole, the molecular formula cannot be determined without additional information about the empirical formula's molar mass relationship.
By determining the molecular mass, then dividing the molecular mass by the formula mass of the empirical formula to determine by what integer the subscripts in the empirical formula must be multiplied to produce the molecular formula with the experimentally determined molecular mass.
You can only calculate the empirical formula because you do not have a mass of this compound given. To do the empirical formula assume 100 grams and change percent to grams. Get moles. 80 grams Carbon (1 mole C/12.01 grams) = 6.66 moles C 20 grams hydrogen (1 mole H/1.008 grams) = 19.84 moles H the smallest becomes 1 in the empirical formula and the other number is divided by it, Thus; H/C 19.84 moles H/6.66 moles C = 2.9, which we call 3 so, CH3 --------------- is the empirical formula To get the molecular formula tour question needed to read; How to calculate molecular formula from such ans such mass of compound with these percentages of elements, Which, of course, your question did not provide. Then you would have divided that given mass by the mass total of the elements of the empirical formula, got a whole number by which you would have multiplied the numbers of your empirical formula to get molecular formula.
To determine the molecular formula from the empirical formula and gram formula mass, first calculate the empirical formula mass of C4H9 (4 carbons + 9 hydrogens). Then, divide the gram formula mass by the empirical formula mass to find the ratio. Finally, multiply the subscripts in the empirical formula by this ratio to get the molecular formula, which in this case is C8H18.
The empirical formula C2OH4 simplifies to C1O2H2. To find the molecular formula, divide the molar mass (88 g/mol) by the empirical formula mass (112 + 216 + 2*1 = 46 g/mol) to get 1.91. This means the molecular formula is approximately 1.91 times the empirical formula, so the molecular formula is C2O4H4.
molar mass over grams of elementThe above answer is somewhat correct. In order to find the molecular formula when given the empirical formula, you must first find the molar mass of the empirical formula.MOLAR MASS# atoms element A x Atomic Mass element A (Periodic Table) = mass A# atoms element B x atomic mass element B (periodic table) = mass B... etc.Add up all of the mass values found above and you have the molar mass.Then, after you have found the empirical formula's molar mass, you divide the molar mass of the molecular formula by the empirical formula's molar mass (solving for n).MOLECULAR FORMULA EQUATION: N (Empirical formula) (read as N times empirical formula) where:N = Molar mass substance---- Molar Mass emp. form.
Yes, if you have some additional information, such as the molecular weight. For instance, the molecules C2H4 and C4H8 have exactly the same percent composition, but they are very different molecules. So you need some other information to tell them apart than the percent composition.Answer ExpandedThis is kind of a trick question. By knowing the percent composition, you would easily be able to determine its empirical formula, but molecular formula is a bit different. The molecular formula is the actual number of atoms in a molecule, so in order to find the specific molecular formula of a substance, you would also need to know how many grams there is of that substance.(This explains the difference between C2H4 and C4H8)
molar mass over grams of elementThe above answer is somewhat correct. In order to find the molecular formula when given the empirical formula, you must first find the molar mass of the empirical formula.MOLAR MASS# atoms element A x Atomic Mass element A (Periodic Table) = mass A# atoms element B x atomic mass element B (periodic table) = mass B... etc.Add up all of the mass values found above and you have the molar mass.Then, after you have found the empirical formula's molar mass, you divide the molar mass of the molecular formula by the empirical formula's molar mass (solving for n).MOLECULAR FORMULA EQUATION: N (Empirical formula) (read as N times empirical formula) where:N = Molar mass substance---- Molar Mass emp. form.
Cannot answer this question without knowing the EMPIRICAL formula.
molar mass of empirical = 7x12 + 9x1 + 16 = 109 g/mole218.078/109 = 2 so there are 2 empirical formulae in 1 molecular formulaThe molecular formula is therefore C14H18O2
We assume 100 grams and turn those percentages into grams and find moles of species. 40 grams carbon (1 mole C/12.01 grams) = 3.33 moles C 6.72 grams hydrogen (1 mole H/1.008 grams) = 6.67 moles H 53.28 grams oxygen (1 mole O/16 grams) = 3.33 The smallest mole number is 1, so we have two small numbers. Divide the large number by the small. 6.67/3/33 = 2 so.............. CH2O is the empirical formula. You did not state that you had a quantity of this compound ( such as 60 grams, or whatever ), so the molecular formula can not be found from this info. C6H12O6 is of course the molecular formula. To find the molecular formula you need a mass of the compound aside from the simple percentages. Then you find, as we have done, the empirical formula. you divide the mass given by the mass of the empirical formula and then take that quotient and multiply it times the empirical formula. In this case (CH2O) * 6 = C6H12O6, the molecular formula
The formula of NO2 has a molecular weight of 46 g/mol. Your compound has a molecular weight of 92 g/mol. As you can see the molecular weight of the compound is twice that of the empirical formula. Therefore the molecular formula of your compound is:2 *(NO2) ---> N2O4