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Actually, the charge of Iodine would be negative one (represented as "1-" in superscript).

Explanation: Iodine is in the second to last column (vertically speaking) to the far right so it is right next to the "nobel gas" column, which is in the total far right column. So Iodine is going to want to be like Xenon (the element to the right of it) because Xenon is stable and Iodine wants to be stable as well. So Iodine will gain another election giving it a total of 54 elections just like Xenon. But, because the elections are negative particles, and Iodine just gained one, that means Iodine's charge is now negative one (1-).

BUT! - an Iodine by itself, as represented by "I2", has a neutral charge, so the charge is 0.

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15y ago

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