Actually, the charge of Iodine would be negative one (represented as "1-" in superscript).
Explanation: Iodine is in the second to last column (vertically speaking) to the far right so it is right next to the "nobel gas" column, which is in the total far right column. So Iodine is going to want to be like Xenon (the element to the right of it) because Xenon is stable and Iodine wants to be stable as well. So Iodine will gain another election giving it a total of 54 elections just like Xenon. But, because the elections are negative particles, and Iodine just gained one, that means Iodine's charge is now negative one (1-).
BUT! - an Iodine by itself, as represented by "I2", has a neutral charge, so the charge is 0.
The acid derived from the IO3- anion is called iodate acid, and its chemical formula is HIO3.
The iodine content ratio of IO3- and I2 is 1 to 2
The formula for stannic iodate is Sn(IO3)4. It consists of one tin (Sn) ion bonded to four iodate (IO3) ions.
MgI2
The chemical formula for platinum iodate is Pt(IO3)4.
The acid derived from the IO3- anion is called iodate acid, and its chemical formula is HIO3.
The iodine content ratio of IO3- and I2 is 1 to 2
The formula for stannic iodate is Sn(IO3)4. It consists of one tin (Sn) ion bonded to four iodate (IO3) ions.
(1.0*10^-14)/(1.6*10^-1)= Kb Kb=6.25*10^-14
MgI2
The chemical formula for platinum iodate is Pt(IO3)4.
The conjugate base of HIO3 is IO3-. When HIO3 donates a proton, it forms the iodate ion, IO3-, by losing a hydrogen ion.
The chemical formula for beryllium iodate is Be(IO3)2.
The chemical formula of ferrous iodate is Fe(IO3)2.
it has it's symbol and valency as IO and -2 respectively. for example the formula of calcium iodate is CaIO.
Probably manganese iodate: Mn(IO3)
Iodic Acid