Magnesium hydroxide. Most people are familiar with it when it is suspended in water to make Milk of Magnesia.
The balanced equation for MgO + H2O is MgO + H2O -> Mg(OH)2.
The compound is called magnesium hydroxide.
To balance the chemical equation Mg(OH)2 + HNO3 → Mg(NO3)2 + H2O, start by balancing the elements other than hydrogen and oxygen. Balance Mg first: Mg(OH)2 + 2HNO3 → Mg(NO3)2 + H2O. Then balance hydrogen by adding 2 molecules of water: Mg(OH)2 + 2HNO3 → Mg(NO3)2 + 2H2O. Finally, balance oxygen by adding 2 more nitric acid molecules: Mg(OH)2 + 2HNO3 → Mg(NO3)2 + 2H2O.
The forumula for magnesium hydroxide is Mg(OH)2
Im assuming you mean Mg(OH)2 and not MgOHThe reaction between Mg(OH)2 and HCl is as follows: Mg(OH)2 (aq) + 2HCl (aq) -> MgCl2 (aq) + 2H2O (l)First the number of mole is found: n(HCl) = c × v = 0.100M × 0.200L = 0.0200mol (to 3 significant figures)Next we find the number of mole of Mg(OH)2:n(Mg(OH)2) ÷ n(HCl) = Coefficient of Mg(OH)2 ÷ Coefficient of HCl n(Mg(OH)2) ÷ n(HCl) = 1 ÷ 2 therefore:n(Mg(OH)2) = (1 ÷ 2) × n(HCl) n(Mg(OH)2) = (1 ÷ 2) × 0.0200moln(Mg(OH)2) = 0.0100mol (to 3 significant figures)Finally we calculate the volume of Mg(OH)2 reacted:v(Mg(OH)2) = n ÷ cv(Mg(OH)2) = 0.0100mol ÷ 0.500MThereforev(Mg(OH)2) = 0.0200L (to 3 significant figures) = 20.0ml (to 3 significant figures)
Mg(OH)2
Mg(OH)2
The balanced equation for MgO + H2O is MgO + H2O -> Mg(OH)2.
The compound is called magnesium hydroxide.
+2
not sure exactly, but it has magnesium, oxygen and iodine
To balance the chemical equation Mg(OH)2 + HNO3 → Mg(NO3)2 + H2O, start by balancing the elements other than hydrogen and oxygen. Balance Mg first: Mg(OH)2 + 2HNO3 → Mg(NO3)2 + H2O. Then balance hydrogen by adding 2 molecules of water: Mg(OH)2 + 2HNO3 → Mg(NO3)2 + 2H2O. Finally, balance oxygen by adding 2 more nitric acid molecules: Mg(OH)2 + 2HNO3 → Mg(NO3)2 + 2H2O.
The forumula for magnesium hydroxide is Mg(OH)2
Im assuming you mean Mg(OH)2 and not MgOHThe reaction between Mg(OH)2 and HCl is as follows: Mg(OH)2 (aq) + 2HCl (aq) -> MgCl2 (aq) + 2H2O (l)First the number of mole is found: n(HCl) = c × v = 0.100M × 0.200L = 0.0200mol (to 3 significant figures)Next we find the number of mole of Mg(OH)2:n(Mg(OH)2) ÷ n(HCl) = Coefficient of Mg(OH)2 ÷ Coefficient of HCl n(Mg(OH)2) ÷ n(HCl) = 1 ÷ 2 therefore:n(Mg(OH)2) = (1 ÷ 2) × n(HCl) n(Mg(OH)2) = (1 ÷ 2) × 0.0200moln(Mg(OH)2) = 0.0100mol (to 3 significant figures)Finally we calculate the volume of Mg(OH)2 reacted:v(Mg(OH)2) = n ÷ cv(Mg(OH)2) = 0.0100mol ÷ 0.500MThereforev(Mg(OH)2) = 0.0200L (to 3 significant figures) = 20.0ml (to 3 significant figures)
Mg(OH)2 is an ionic compound. Magnesium (Mg) is a metal that tends to lose electrons to form a cation (Mg^2+), while hydroxide (OH) is a polyatomic ion that tends to gain electrons to form an anion (OH^-). Therefore, Mg(OH)2 is composed of ionic bonds between the magnesium cation and the hydroxide anions.
Mg(Si2O5)2.Mg(OH)2
Mg(oh)2 contains of Mg,O and h atoms. There are 3 atoms in 1 Mg(OH)2. So there are 12 atoms in 4Mg(OH)2.