answersLogoWhite

0

Ca(NO3)2 is the chemical formula of calcium nitrate.

User Avatar

Wiki User

9y ago

What else can I help you with?

Related Questions

How many atoms of oxygen are in 0.50 mol of CaNO32?

The answer is 18,061.1023 atoms.


Does an aqueous solution of CaNO32 and tin metal react?

A reaction doesn't occur.


How many calcium atoms are in the compound CaNO32?

There are three calcium (Ca) atoms in the compound Ca(NO3)2.


What contains the greatest number of molecules out of 0.5 mol CaNO32 or 2.3 mol H2O or 1.2 mol H2O2?

The answer is 2,3 moles water.


Is CaNO32 a basic salts?

no as it is a salt of Ca(OH)2 and HNO3 so it is a salt of strong acid and strong base . so it is not basic in my opinion


How many grams of calcium phosphate are theoretically produced if you start with 10.3 moles of CaNO32 and 7.6 moles of Li3PO4?

735 g of Ca3(PO4)2 are obtained.


What compounds is insoluble in water kcl potassium chloride agcl silver chloride na2co3 sodium carbonate cano32 calcium nitrate?

Silver chloride (AgCl) is insoluble in water.


What is CANO32?

CaNO3 does not exist. Ca(NO3)2 is calcium nitrate.


The molar mass of CaCO3 is greater than the molar mass of CaNO32?

No, this statement is incorrect. The molar mass of CaCO3 (calcium carbonate) is 100.09 g/mol, while the molar mass of Ca(NO3)2 (calcium nitrate) is 164.08 g/mol. Therefore, the molar mass of Ca(NO3)2 is greater than that of CaCO3.


How many atoms of oxygen are in one formula unit of CaNO32?

Three oxygen atoms in each nitrate ion multiplied by two nitrate ions results in 6 total oxygen atoms.


What is the complete ionic formula for the reaction between CaNO32 and NH4Br?

The complete ionic formula for the reaction between Ca(NO3)2 and NH4Br is: Ca^2+ + 2NO3^- + 2NH4+ + 2Br^- -> Ca(NO3)2 + 2NH4Br


Which equation represents the oxidation half-reaction for this redox reaction Ca plus AlNO33 Al plus CaNO32?

In the given redox reaction, calcium (Ca) is oxidized to calcium ions (Ca²⁺). The oxidation half-reaction can be represented as: [ \text{Ca} \rightarrow \text{Ca}^{2+} + 2e^- ] This shows that solid calcium loses two electrons as it is converted into calcium ions.